All categories

4 years ago

Round 0.424 to the nearest tenth

Mathematics

2 answers:

Advocard [28]4 years ago

6 0

The answer is 0.4 :)

lakkis [162]4 years ago

5 0

0.424 rounded to nearest tenth would be 0.4 as you can not round up because the hundredth place is not 5 or higher

You might be interested in

9,-2 and -3,2 point slope form

VMariaS [17]

Answer:

y+2=-1/3 x (x-9)

Step-by-step explanation:

This answer is 99% correct.

8 0

3 years ago

Which equation is represented by the graph?

Elina [12.6K]

Answer:

$y = - |x| + 2$

Step-by-step explanation:

The graph is similar to Parabola. The transformation of graph is also similar to Parabola.

For B choice, the graph doesn't move by y-axis.

For C choice, the graph would have max-point at -2.

For D choice, similar to the B choice.

8 0

3 years ago

90sec equal to how many min

Kruka [31]

Answer:

1 minute and 30 sec

Step-by-step explanation:

because there are 60 seconds in a minute and 60+30 is 90

5 0

3 years ago

Read 2 more answers

Returned merchandise to Starcraft Industries, $560. 15 Returned merchandise to XYZ, Inc., $400. 27 Returned merchandise to Datam

rusak2 [61]

The appropriate journal entries to record the transactions are: Debit Accounts Payable/Starcraft Industries $560; Credit Purchases Returns and Allowances $560.

<h3>Journal entries</h3>

Jul. 7

Debit Accounts Payable/Starcraft Industries $560

Credit Purchases Returns and Allowances $560

Jul. 15

Debit Accounts Payable/ XYZ, Inc. $400

Credit Purchases returns and allowances $400

Jul 27

Debit Accounts Payable/ Datamagic $900

Credit Purchases returns and allowances $900

Therefore the entries to record the transactions are: Debit Accounts Payable/Starcraft Industries $560; Credit Purchases Returns and Allowances $560.

Learn more about journal entries here:brainly.com/question/14279491

#SPJ1

5 0

2 years ago

Sam initially invested $4,500 into a savings account that offers an interest rate of 3% each year. He wants to determine the num

choli [55]

$\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill&7020\\ P=\textit{original amount deposited}\dotfill & \$4500\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\dotfill \end{cases}$

$\bf 7020\geqslant 4500(1+0.03t)\implies \cfrac{7020}{4500}\geqslant 1+0.03t\implies \cfrac{39}{25}\geqslant 1+0.03t \\\\\\ \cfrac{39}{25}-1\geqslant 0.03t\implies \cfrac{14}{25}\geqslant 0.03t\implies \cfrac{~~\frac{14}{25}~~}{0.03}\geqslant t\implies \cfrac{56}{3}\geqslant t \\\\\\ 18\frac{2}{3}\geqslant t\impliedby \textit{18 years and 8 months}~\hfill \boxed{0 \leqslant t \leqslant 18\frac{2}{3}} \\\\\\ ~\hspace{34em}$

check the picture below.

bearing in mind that "t" cannot be less than 0.

8 0

3 years ago