Answer:
C(3,-4), r=4*sqrt(2)
Step-by-step explanation:
C(p, q)
x^2+y^2+dx+ey+f=0
p=-d/2, q=-e/2, r^2=p^2+q^2-f
x^2+y^2 - 6x+8y-7=0
p=-(-6)/2=6/2=3
q=-8/2=-4
r^2=3^2 +(-4)^2+7
r^2=9+16+7
r^2=32
r=sqrt(32)
r=sqrt(16*2)
r=4*sqrt(2)
Domain is [-10,∞)
2 is included , only at x=2 new function begins
Range is the values of y , so range is [-7]∪[-4,6
I think, it should be like this.
Answer:
The zeros are 6,-5,9
Step-by-step explanation:
The factored form of the polynomial is given as:

To find the zeros of this function, we set f(x)=0 and solve for x.

This implies that:

We solve for x to get:

The zeros are 6,-5,9
<h2>The third graph</h2><h3 /><h3>The graph has a slope of 2</h3><h3>and a y-intercept of -4</h3>