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3 years ago

How many solutions are there to the equation below?

2 answers:

8 0

Hello there.
Happy Valentine's Day⸮❍◡❍?

How many solutions are there to the equation below?
220 = 2x-12x

A) 1

NARA [144]3 years ago

6 0

There is only one solution and the solution is x=-22

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A triangle has sides with length of 5 yards,14 yards,and 16 yards.is it a right triangle

Anna35 [415]

Answer:

As the largest side is

yards and smaller sides are

yards and

yards

from Pythagoras theorem, if the triangle is right angled square of largest side should be equal to sum of the squares of smaller two sides.

Square of largest side is

225

and squares of smaller two sides are

and

144

225

144

, the triangle is right angled.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the unit rate for meters per second if a car travels 480 meters in 24 seconds?

Yanka [14]

20 meters per second

8 0

3 years ago

Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin

jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

GIVEN :-

There are 2 right-angled triangles.

In the triangle on the right side ,

Hypotenuse = 26m
Base = 10m

In the triangle on the left side ,

Base = 18m

TO FIND :-

Length of the common perpendicular to both triangles.
Length of the hypotenuse of the triangle on the left side.

FACTS TO KNOW BEFORE SOLVING :-

$Hypotenuse = \sqrt{Base^2 + Perpendicular^2}$ .
$Perpendicular = \sqrt{Hypotenuse^2 - Base^2}$

SOLUTION :-

In the triangle on the right side ,

$Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m$

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

$Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m$

∴ x = 30m

3 0

3 years ago

The altitude of a triangle is increasing at a rate of 3 centimeters/minute while the area of the triangle is increasing at a rat

sp2606 [1]

The base of the triangle is decreasing at a rate of 3.60 centimeters/minute.

According to the statement

we have to find that the rate at which the base of triangle changing.

So, For this purpose,

Area of triangle: A = (1/2)(b * h)

Related Rates - Derivative with respect to time:

(d/dt)[A = (1/2)(b * h)]

Then

dA/dt = (1/2)[b * dh/dt + h * db/dt]

Given: h = 11 centimeters, A = 91 square centimeters, b = ??

A = (1/2)(b * h)

Then it becomes

b = 2A/h

substitute the value then

b = 2(91)/11

b = 16.54 centimeters

Then

h = 11 centimeters, b = 16.54 centimeters, dA/dt = 5 square centimeters/minute, dh/dt = 3 centimeters/minute, db/dt = ?? centimeters/minute

So,

(d/dt)[A = (1/2)(b * h)]

Then it become

dA/dt = (1/2)[b * dh/dt + h * db/dt]

5= (1/2)[16.54 * 3 + 11 * db/dt]

5= 49.62/2 + 11/2 * db/dt

11/2 * db/dt = 5- 49.62/2

5.5*db/dt = 5 - 24.81

db/dt = -19.81/5.5

db/dt = -3.60 centimeters/minute

So, The base of the triangle is decreasing at a rate of 3.60 centimeters/minute.

Learn more about base of triangle here

brainly.com/question/23945265

#SPJ4

7 0

1 year ago

I want to know algebra

GarryVolchara [31]

Answer:

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5 0

3 years ago