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pentagon [3]
3 years ago
7

Need help will give 15 points

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

Answer:

y = -2/3x + 6

Step-by-step explanation:

To find the slope, find how much y changes in proportion to x. Here, when x changes by 1, y changes by -2/3. So, the number before x is -2/3.

To find the y-intercept, we need to find what y will be when x is 0. Since we know that when x is 1, y is 16/3, and when x decreases by 1, y increases by 2/3. So, when x is 0, y is 16/3 + 2/3, which is 18/3, or 6.

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What is the side length of a square with an area of 144x^2?
zvonat [6]
To answer this, we need to know the expression for the area of a square which is the square of its side length or:

Area = a²

Solving for the side length,

a = √area
a = √144x²
a = 12x

Therefore, the side length is 12x.
6 0
3 years ago
7=8 + r/15 <br> Simplify, with steps pleaseee
Crazy boy [7]

Answer:

7 = 8 +  \frac{r}{15}  \\ 7 - 8 =  \frac{r}{15}  \\  - 1 = \frac{r}{15}  \\  \therefore \: r =  - 15

8 0
2 years ago
Read 2 more answers
2x-2&lt;-12or2x+3&gt;7 what is the solution to this compound inequality
cluponka [151]

2x-2 < -12\qquad|+2\\\\2x < -10\qquad|:2\\\\x < -5

-----------------------------------------------------------------------------------------------

2x+3 > 7\qquad|-3\\\\2x > 4\qquad|:2\\\\x > 2


Answer:\ x < -5\ or\ x > 2

8 0
3 years ago
F(x) = 3x3 - 5x2 +6x -12
arlik [135]

Answer:

1.79438504

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP!!!! 20 POINTS!!!!
galben [10]
These are two questions and two answers.

Question 1) Which of the following polar equations is equivalent to the parametric equations below? 

<span> x=t²
y=2t</span>

Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>

Explanation:

1) Polar coordinates ⇒ x = r cosθ and y = r sinθ

2) replace x and y in the parametric equations:

r cosθ = t²
r sinθ = 2t

3) work r sinθ = 2t

r sinθ/2 = t 
(r sinθ / 2)² = t²

4) equal both expressions for t²

r cos θ = (r sin θ / 2 )²

5) simplify

r cos θ = r² (sin θ)² / 4

4 = r (sinθ)² / cos θ

r = 4 cosθ / (sinθ)²

r = 4 cot θ csc θ ↔ which is the option A.


Question 2) Which polar equation is equivalent to the parametric equations below?

<span> x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>

Answer: option B) r = sinθ + 1


Explanation:

1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ

2) replace x and y in the parametric equations:

a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span> b) r sinθ =sin²(θ)+sin(θ)</span>

3) work both equations

a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1]  ⇒ r = sinθ + 1


<span> b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
6 0
3 years ago
Read 2 more answers
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