What is the quotient for 18/1000

Mathematics

2 answers:

8_murik_8 [283]3 years ago

5 0

well the quotient means the answer to a division, so in this case:

18 ÷ 1000 = 0.018

Taya2010 [7]3 years ago

5 0

THE ANSWER IS 0.18.THE REASON WHY ITS 0.18 BECAUSE 100 GOES TO 18 ZERO TIMES.ADD A DECIMAL POINT TO 18 TO LOOK LIKE 18.0.BRING THE ZERO DOWN BECAUSE 100 CAN GO TO 180 ONE TIME. SUBTRACT 180 AND 100 YOU GET 80. PUT ANOTHER ZERO TO 80 YOU GET 800 .100 CAN GO TO 800 8 TIMES.SO 0.18 IS YOUR QUOTIENT!

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noname [10]

Answer:

Step-by-step explanation:

So lets use the process of elimantion to find the answer.

Firs off, we can tell that this is a greater/less than or equal to inequlaity, since there is a inclosed circle, not a open one. So this leaves the top left answer and bottem right answer.

Now, we can see that the graph is from 0-15. X is at 7.

This means its x+8, because the x would be smaller, or possibly even negatibe on this graph.

My theory that can better support my annwer is if we solve for x:

x+8=15

We can subtract 8 from both sides:

x=7

And as we can see on the inequality, x is at 7 in the graph.

Hope this makes sense and helps!

6 0

3 years ago

What’s is the solution to the equation x to the power of 2 =16/25

skelet666 [1.2K]

Answer:

$x=\dfrac{4}{5}$

Step-by-step explanation:

The given equation is :

$x^2=\dfrac{16}{25}$

We need to find the value of x.

When the exponent 2 removes from LHS, it will shift to RHS as square root as follows :

$x=\sqrt{\dfrac{16}{25}}$

We know that, 4×4= 16 and 5×5 = 25

So,

$x=\sqrt{\dfrac{4\times 4}{5\times 5}}\\\\x=\dfrac{4}{5}$

So, the solution of the given equation is 4/5.

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2 years ago

What is the oblique asymptote of the function f(x) x^2+x-2/x+1

Mamont248 [21]

$f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}
$

$\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0$

Consequently, the limit of $f(x)$ as x approaches infinity is $x$ .

In other words, $f(x)$ approaches the line y=x,

so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.