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atroni [7]
3 years ago
7

What is the quotient for 18/1000

Mathematics
2 answers:
8_murik_8 [283]3 years ago
5 0


well the quotient means the answer to a division, so in this case:

18 ÷ 1000 = 0.018

Taya2010 [7]3 years ago
5 0
THE ANSWER IS 0.18.THE REASON WHY ITS 0.18 BECAUSE 100 GOES TO 18 ZERO TIMES.ADD A DECIMAL POINT TO 18 TO LOOK LIKE 18.0.BRING THE ZERO DOWN BECAUSE 100 CAN GO TO 180 ONE TIME. SUBTRACT 180 AND 100 YOU GET 80. PUT ANOTHER ZERO TO 80 YOU GET 800 .100 CAN GO TO 800 8 TIMES.SO 0.18 IS YOUR QUOTIENT!
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Which expressions are equivalent to 16x4 − 64? Check all that apply. 16x4 + 16x – 16x – 64 16x4 – 8x – 8x – 64 (4x2 + 8)(4x2 – 8
KengaRu [80]

Answer:

16x4 + 16x – 16x – 64

16x4 – 8x – 8x – 64

(4x2 + 8)(4x2 – 8)

16(x2 + 2)(x2 – 2)

7 0
3 years ago
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Step-by-step explanation:

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2 years ago
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Anastaziya [24]
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7 0
3 years ago
By selling a cow for Rs 144, there is a profit of the same percentage as its cost price. Find the cost price.​
hjlf

Answer:

Step-by-step explanation:

<h2><u>☼︎</u><u>Answer:</u></h2>

The cost price of cow = Rs.80

Explanation:

<h2><u>☼︎</u><u>Given :-</u></h2>

  • By selling a cow for Rs 144, there is a profit of the same percentage as its cost price.
<h2><u>☼︎</u><u>T</u><u>o Find</u><u>:</u><u>-</u></h2>

  • The cost price.
<h2 /><h2 /><h2><u>☼︎</u><u>L</u><u>e</u><u>t</u><u>:</u><u>-</u></h2>

  • The cost price of cow = Rs.x

<h2><u>☼︎</u><u>Solution :-</u></h2>

\sf x + x \: of \: x\%= 144 \\ \\ \sf \implies x + \frac{x \times x}{100} = 144 \\ \\ \sf \implies {x}^{2} + 100x - 14400 = 0 \\ \\ \sf \implies x(x - 80) + 180(x - 80) = 0 \\ \\ \sf \implies x + 180 = 0 \\ \\ \sf \implies x = - 180 \\ \\ \sf \therefore \:  {\boxed{ \sf \pink{x = 80}}}

<h2><u>Hence: </u></h2>

The cost price of cow =<u>R</u><u>s</u><u>8</u><u>0</u>

4 0
3 years ago
Read 2 more answers
HELP PLEASE WILL MARK BRAINLIEST!!
Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

from \: the \: figure \\ AB = 300 \: ft \:  \:  \: angle \: C = 60  \:( theta)\: degress \\ in \: triangle \: ABC \: using \:  tan \: theta\\  \tan(60)  =  \frac{opposite \: side}{adjacent \: side}  \\  \tan(60)  =  \frac{300}{BC}  \\  \sqrt{3}  =  \frac{300}{BC}  \\ BC =  \frac{300}{ \sqrt{3} }  \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\   \tan(30 )  =\frac{opposite \: side}{adjacent \: side} \\  \tan(30)   =  \frac{300}{BD}  \\  \frac{1}{ \sqrt{ 3} }  =  \frac{300}{BD}  \\ BD = 300 \sqrt{3}  \\ CD = BD - BC \\  = 300 \sqrt{3 }  - 100 \sqrt{3}  \\  = (300 - 100) \sqrt{3}  \\  = 200 \sqrt{3 }  \\  = 200 \times 1.732 \\  = 346.4 \: ft

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
3 years ago
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