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Over [174]
3 years ago
15

Is 16:14 in 64:60 eqiluvant

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

16: 14 - divide by 2

16/2= 8 , 14/2=7

64:60- divide by 4

64/4= 16 , 60/4= 15

Answer: 16:14 and 64:60 are not equivalent.

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The measures have been substituted in the formula for
Fudgin [204]

Answer: 27,488.94 cubic feet

Step-by-step explanation: i just took it

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3 years ago
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Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at
kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event  

- The probability of an Event = Number of favorable outcomes ÷ Total

 number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A  

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

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∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

  choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0
3 years ago
Read 2 more answers
The actual length of the rectangle below is 41 cm. Using the scale drawing below, find the actual width.
Margaret [11]

Okay, so your scale rectangle has a length of l = 8.2 cm. The actual triangle has a length of L = 41 cm. What is the scale factor? You find out by dividing the scale rectangle l from the actual rectangle L.

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The scale factor is 5. That means the actual rectangle is exactly 5 times bigger than the scale rectangle. Now finding the width is easy! If the width of the scale rectangle is 2.1 cm and the scale factor is 5, you just multiply them together!

2.1 cmx 5 = 10.5 cm

The width of the actual rectangle is 10.5 cm! Hope that helps!

7 0
3 years ago
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Can someone help me on this please.
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In circle O, TM = CB. If mTM = 4x - 11 and<br>mCB = 3x + 19, what is the measure of TM?<br>​
dangina [55]
Think the answer is actually 0
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