Answer:
Incomplete question, check attachment for the necessary diagram
Step-by-step explanation:
Note in the attachment,
We have two identical straight line of lenght
L1 = L2 = 84.39m
We also have two identical semicircle or radius 36.5m to the first track lane
But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m
So, radius = 36.5+6
r = 42.5m
Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2
P = 2πr/2
P =πr
P = 22/7 × 42.5
P = 133.57 m
Then, the arc 1 is equal to arc 2 which is equal to 133.57 m
A1 = A2 = 133.57 m
Now we have all the dimensions,
Then, the perimeter can be calculated by adding the length of the sides
The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc
P = L1 + L2 + A1 + A2
P = 84.39 + 84.39 + 133.57 + 133.57
P =435.923 m
So, to the nearest meter
P ≈ 436m
The perimeter of the track is 436m
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