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3 years ago

13

Angl is a square. The equation of line NG is Y= 1/2 X - 6. Find the equation of line LG in slope intercept form given that the c

oordinates of L are (-5,1)

1 answer:

Irina18 [472]3 years ago

3 0

Answer: y=-2x-9

Step-by-step explanation:

If ANGL is a square, then NG and LG are adjacent sides.

Adjacent sides are perpendicular. [Each angle is 90°]

The equation of line NG is $Y=\dfrac12 X-6$ .

By comparing it to equation in slope intercept form y=mx+c ( where , m= slope , c=y-interecpt)

slope = $\dfrac12$

Let slope of LG be <em>n</em>, then

$n\times \dfrac{1}{2}=-1$ [Product of slopes of two perpendicular line =-1]

$\Rightarrow n=-2$

Equation of a line passes through (a,b) and have slope m is given by :-

$(y-b)=m(x-a)$

Equation of LG :

$(y-1)=-2(x-(-5))\\\\\Rightarrow\ y-1=-2x-10\\\\\Rightarrow\ y=-2x-9$ [In intercept form]

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$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

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