Answer:
nothing
Step-by-step explanation:
nothing
Answer: 
Step-by-step explanation:
1. By definition, two slopes are perpendicular if their slopes are negative reciprocals of each other. So, let's find the slope of the other line.
2. The equation given in the problem is written in Point-slope form:

Where m is the slope.
3. Therefore, the slope of its perpendicular line must be:

4. You have the point (-5,7), so you can substitute it into the point-slope formula to find the equation of the new line:

5. In slope intercept form is:

Y=a(x-h)^2+k
is what vertex form look like. (h,k) is your vertex so in this problem your vertex would be (60,200)
Answer:
Therefore the angle that the line through the given pair of points makes with the positive direction of the x-axis is 45°.
Step-by-step explanation:
Given:
Let
A(x₁ , y₁) = (1 , 4) and
B( x₂ , y₂ ) = (-1 , 2)
To Find:
θ = ?
Solution:
Slope of a line when two points are given is given bt

Substituting the values we get

Also Slope of line when angle ' θ ' is given as

Substituting Slope = 1 we get


We Know That for angle 45°,
tan 45 = 1
Therefore

Therefore the angle that the line through the given pair of points makes with the positive direction of the x-axis is 45°.