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Kisachek [45]
3 years ago
11

The French club is sponsoring a bake sale. If their goal is to raise at least $135, how many pastries must they sell at $2.50 ea

ch in order to meet that goal? Write and solve an inequality.
Mathematics
2 answers:
Vesnalui [34]3 years ago
4 0
Let x be the amount they must sell

X * 2.5 ≥ 135
X ≥ 54
Katena32 [7]3 years ago
4 0
The answer should be 135/2.50 = 1350/25 = (4*1350)/(4*25) = 5400/100 = 54

So answer will be 54 pastries
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IceJOKER [234]

Answer:

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Hope that helps

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2 years ago
WILL SOMEONE PLZ HELP ME!! I'VE ASKED LIKE 5 TIMES NOW!!! Approximately how long will it take you to double your savings of $500
USPshnik [31]

Answer:

18 years

Step-by-step explanation:

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2 years ago
What is true of the data in the dot plot? Check all that apply.
otez555 [7]

True answers for data in the plot are

The center is 13

The center is not 14

The Peak is 14.

It has three clusters

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Total number times Shelly waited is 16 times.

Step-by-step explanation:

  • While taking cumulative frequency 56.75 percentage comes in 13%.
  • It is the center point of the data.
  • The 14  is not the center as it shows 93rd percent.
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8 0
3 years ago
Read 2 more answers
The inchworm moves 1/5 inch per hour. How far will the inchworm have moved after 6 hours?
melisa1 [442]

Answer: 1 1/5 inches.

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5 0
2 years ago
The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that
Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

  • 6% of the city's population moves to the suburbs (and 94% stays in the city).
  • 2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

A= \left \begin{array}{cc}  \\ C \\S \end{array} \right\left[ \begin{array}{cc}  C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]

The population in the  year 2000 (initial state) is given as:

\left[ \begin{array}{cc}  C&S\\ 500,000&700,000  \end{array} \right]

Therefore, the population of the city and the suburb in 2002 (two years after) is:

S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2

A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]

Therefore:

S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0
3 years ago
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