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Tomtit [17]
2 years ago
9

Find the slope of a parallel line to each given line y=-1/3x-4

Mathematics
2 answers:
Mumz [18]2 years ago
4 0
Slope of parallel line to this would be -1/3x
Eduardwww [97]2 years ago
4 0

Answer:

3

Step-by-step explanation:

3x-y =4

-y= 3x - subtract 3x from both sides

y= 3x - 4 multiply both sides by -1

the slope is 3

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Does the equation 6x + 35 = -6x - 35 have no, one, or infinite solutions?
fenix001 [56]

Answer:

The equation has one solution.

Step-by-step explanation:

6x + 35 = -6x - 35

subtract 6x from both sides of the equation

35 = -35 - 12x

add 35 to both sides of the equation

70 = -12x

divide -12x on both sides of the equation

x = 5.833333333

6 0
2 years ago
Which of the following values is the solution of x/32=8?<br> a 24<br> b 40<br> c 256<br> d 4
Oduvanchick [21]

Answer:

c) 256

Step-by-step explanation:

https://www.tiger-algebra.com/drill/x/32=8/ This link shows you how it’s done, it’s not some random link, i used the website all the time

4 0
3 years ago
2x+ 20 + 3x +40 =<br> 60 + 5X
umka21 [38]
First answer: 160
Second answer: 300
6 0
3 years ago
Charles will babysit for up to 4 hours and charges $7 per hour. Write a function in function notation for this situation.
I am Lyosha [343]
Assume Charles charges $7*3=$21 if he babysits for 2,5 hours (that is 2 and a half hours).

That is we are not considering Charles babysitting exactly 1, 2, 3 or 4 hours, but also in between times.


then we can write the following piecewise function to describe the situation:


f is a function from (0, 4] to {$7, $14, $21, $28}

f(x)=\begin{cases} &#10;      \$7 & if \enspace \enspace x\leq 1 \\&#10;      \$14 & if \enspace \enspace 1\ \textless \  x\leq 2 \\&#10;      \$21 & if \enspace\enspace 2\ \textless \ x\leq 3 \\&#10;      \$28 & if \enspace\enspace 3\ \textless \ x\leq 4 \&#10;   \end{cases}
6 0
3 years ago
The function h ( x ) = 1 x − 1 h ( x ) = 1 x - 1 can be expressed in the form f ( g ( x ) ) f ( g ( x ) ) , where g ( x ) = ( x
Radda [10]

Answer: f(x) = 1^(x + 1)

Step-by-step explanation:

we have that h(x) = 1^x

and h(x) = f(g(x))

This mean that we are evaluating the function f(y) in the point y = g(x)

where g(x) = x - 1

then:

f(g(x) = f(x - 1) = h(x) = 1^x

then we should have that:

f(x) = 1^(x + 1)

then:

f(x - 1) = 1^(x - 1 + 1) = 1^x

4 0
3 years ago
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