Answer:
When kicked, the height of the ball is 1 feet. The highest point for the ball's trajectory is 12 feet.
Step-by-step explanation:
We are given that the height is given by
. The distance between the ball to the point where it was kicked is 0 right at the moment the ball was kicked. So, the height of the ball, when it was kicked is f(0) = -0.11*0 + 2.2*0 +1 = 1.
To determine the highest point, we will proceed as follows. Given a parabola of the form x^2+bx + c, we can complete the square by adding and substracting the factor b^2/4. So, we get that
.
In this scenario, the highest/lowest points is ![c-\frac{b^2}{4}[/tex} (It depends on the coefficient that multiplies x^2. If it is positive, then it is the lowest point, and it is the highest otherwise). Then, we can proceed as follows. [tex] f(x) = -0.11x^2+2.2x+1 = -0.11(x^2-20x)+1](https://tex.z-dn.net/?f=c-%5Cfrac%7Bb%5E2%7D%7B4%7D%5B%2Ftex%7D%20%28It%20depends%20on%20the%20coefficient%20that%20multiplies%20x%5E2.%20If%20it%20is%20positive%2C%20then%20it%20is%20the%20lowest%20point%2C%20and%20it%20is%20the%20highest%20otherwise%29.%20%3C%2Fp%3E%3Cp%3EThen%2C%20we%20can%20proceed%20as%20follows.%20%3C%2Fp%3E%3Cp%3E%5Btex%5D%20f%28x%29%20%3D%20-0.11x%5E2%2B2.2x%2B1%20%3D%20-0.11%28x%5E2-20x%29%2B1)
We will complete the square for
. In this case b=-20, so

We can distribute -0.11 to the number -100, so we can take it out of the parenthesis, then

So, the highest point in the ball's trajectory is 12 feet.