I was stuck on the same thing in my class test. I ended up failing but if I get the answers to it I’ll totally send them to you!!!
Answer:
The number of marbles Richard has 24 and John has 6.
Step-by-step explanation:
Richard has four times as many marbles as john.
If Richard have 18 to John they would have the same number.
Now, to find number of marbles each has.
Let the marbles of John be 
.
And the marbles of Richard be 
According to question:
<em>Subtracting both sides by we get:</em>
<em>Dividing both sides by 3 we get:</em>
<u><em>Marbles of John</em></u><em> = 
</em>
<u><em>Marbles of Richard</em></u><em> = 
</em>
Therefore, the number of marbles Richard has 24 and John has 6.
It looks like your equations are
7M - 2t = -30
5t - 12M = 115
<u>Solving by substitution</u>
Solve either equation for one variable. For example,
7M - 2t = -30 ⇒ t = (7M + 30)/2
Substitute this into the other equation and solve for M.
5 × (7M + 30)/2 - 12M = 115
5 (7M + 30) - 24M = 230
35M + 150 - 24M = 230
11M = 80
M = 80/11
Now solve for t.
t = (7 × (80/11) + 30)/2
t = (560/11 + 30)/2
t = (890/11)/2
t = 445/11
<u>Solving by elimination</u>
Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,
7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)
5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)
Now combining the equations eliminates the t terms, and
(-10t + 35M) + (10t - 24M) = -150 + 230
11M = 80
M = 80/11
It follows that
7 × (80/11) - 2t = -30
560/11 - 2t = -30
2t = 890/11
t = 445/11
Answer:
What’s the question
Step-by-step explanation:
It would be the fourth answer -6(2)=-13 I think
