Answer:
expanding ends in the simplest form: 24p-36
Step-by-step explanation:
3 to the square root of 5
When we are multiplying the two numbers, we should notice that they share the same base. Because of this, we can add the exponents when we multiply them.
Answer:
y = 
Step-by-step explanation:
Given
6 | 5y - 1 | - 1 = 29 ( add 1 to both sides )
6 | 5y - 1 | = 30 ( divide both sides by 6 )
| 5y - 1 | = 5
The absolute value function always returns a positive value. However, the expression inside can be positive or negative, thus
5y - 1 = 5 ( add 1 to both sides )
5y = 6 ( divide both sides by 5 )
y = 
OR
- (5y - 1) = 5, that is
- 5y + 5 = 5 ( subtract 5 from both sides )
5y = 0 ⇒ y = 0
As a check substitute these values into the left side and if equal to the right side then they are the solutions.
x = 0 : 6|0 - 1 | - 1 = 6 | - 1| - 1 = 6(1) - 1 = 6 - 1 = 5 ≠ 29
x =
: 6 | 6 - 1 | - 1 = 6(5) - 1 = 30 - 1 = 29
Thus x =
is a solution, x = 0 is extraneous
Answer:
5.5
Step-by-step explanation:
4(x+2)=30
4x+8=30
4x=30-8
4x=22
x=22/4
x=5.5
The price of 1 hat is $ 5 and price of 1 t-shirt is $ 8
<em><u>Solution:</u></em>
Let "s" be the price of 1 shirt
Let "h" be the price of 1 hat
<em><u>Given that Jones buys 7 t-shirts and 6 hats for $86</u></em>
Therefore, we can frame a equation as:
price of 1 shirt x 7 + price of 1 hat x 6 = 86

7s + 6h = 86 ------ eqn 1
<em><u>Also given that The price of each t shirt is $3 more than the price of each hat</u></em>
price of 1 shirt = 3 + price of 1 hat
s = 3 + h -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
7( 3 + h ) + 6h = 86
21 + 7h + 6h = 86
21 + 13h = 86
13h = 86 - 21
13h = 65
<h3>h = 5</h3>
From eqn 2,
s = 3 + h = 3 + 5 = 8
<h3>s = 8</h3>
Thus price of 1 hat is $ 5 and price of 1 t-shirt is $ 8