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3 years ago

11, -15 = 5130 - 107 - 50 12.

Mathematics

1 answer:

TiliK225 [7]3 years ago

6 0

There is not enough given in order to solve. What are you asking?

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A professional football team has 53, players, 24 coaches, and 32 cheerleaders.

madam [21]

Answer:

53:24

Step-by-step explanation:

53 is a prime number so the ratio is already in simplest form.

4 0

3 years ago

luke has $1.40 in quarters and nickels. he has 2 more quarters than nickels. how many coins of each type does he have?

Ainat [17]

Answer:

3 nickels and 5 quarters

Step-by-step explanation:

Let n = number of nickels

q = number of quarters

q = n+2

.25q + .05n = 1.40

Using the first equation and replacing q in the second equation

.25( n+2) + .05n = 1.40

Distribute

.25n+.50 +.05n = 1.40

Combine like terms

.30n +.5 = 1.40

Subtract .5 from each side

.3n +.5-.5 = 1.40-.4

.3n = .9

Divide by .3

.3n/.3 = .9/.3

n = 3

q = n+2

q=5

8 0

3 years ago

Read 2 more answers

Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a

NARA [144]

$x^3y^2+\sin(x\ln y)+e^{xy}=0$

Differentiate both sides, treating $y$ as a function of $x$ . Let's take it one term at a time.

Power, product and chain rules:

$\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}$

$=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}$

$=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}$

$=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)$

$=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}$

$=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)$

$=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}$

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

$3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0$

Isolate the derivative, and solve for it:

$\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}$

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by $y$ to get rid of that fraction in the denominator.

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}$

3 0

3 years ago

Jim adds 20 to it, then doubles it and gets an answer of 99.2. What was the original number?

riadik2000 [5.3K]

(n+20)*2 = 99.2

distribute

2n + 40 = 99.2

subtract 40 from each side

2n = 59.2

divide each side by 2

n = 29.6

7 0

3 years ago

Solve. *25 points*<br><br> 1/2 divided by 2/3 =?

Colt1911 [192]

Answer:

The answer is 3/4

Step-by-step explanation:

When you divide two fractions, such as 1/2 ÷ 2/3, you have to flip the second fraction and then you simply multiply the numerators with each other and the denominator with each other.

7 0

3 years ago