A. (2,6)(5,0)
slope = (0 - 6) / (5 - 2) = -6/3 = -2
y = mx + b
slope(m) = -2
(2,6)..x = 2 and y = 6
sub and find b, the y int
6 = -2(2) + b
6 = -4 + b
6 + 4 = b
10 = b
so line A , equation is : y = -2x + 10
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B. (0,2)(6,6)
slope = (6 - 2) / (6 - 0) = 4/6 which reduces to 2/3
y = mx + b
slope(m) = 2/3
(0,2)...x = 0 and y = 2
sub and find b, the y int
2 = 2/3(0) + b
2 = b
LIne B, equation is : y = 2/3x + 2
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so we have :
y = 2/3x + 2
y = -2x + 10
2/3x + 2 = -2x + 10 ..multiply by 3
2x + 6 = -6x + 30
2x + 6x = 30 - 6
8x = 24
x = 24/8
x = 3
y = -2x + 10
y = -2(3) + 10
y = -6 + 10
y = 4
solution is (3,4).....3/4 is the solution to both lines <===
Answer:
-7
Step-by-step explanation:
(1/2)2−6(2−2/3)
1- 6(4/3)
1- (24/3)
-7
It is the steps to get to that certain step
some of the steps are out of order
I'm going to assign letters
the order is
A: 2x+5=19
B: 2x+5-5=19-5
C: 2x=14
D: 2x/2=14/2
E: x=7
A: given
B: we subtracted 5 from both sides so subtraction property of equality
C: subtract
D: divison property of equality (we divide both side by 2)
E: divide
<h3>
Answer: Choice A) e^c = 4</h3>
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In general if we had something like x = ln(y), then it is equivalent to e^x = y or y = e^x. The Ln is a natural log that is the inverse of the base e exponent. It's a special kind of log.
In this case, x = c and y = 4
So we go from c = ln(4) to e^c = 4
note: Logs are often used to solve for equations with variables in the exponent.
