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4 years ago

Analyze the linear inequalities and determine if the solution set is the shaded region above or below the boundary line.

Mathematics

1 answer:

KengaRu [80]4 years ago

7 0

Hello!

If the y side is greater than the x side then it is shaded above

If the x side is greater than the y side then it is shaded below

So the answers are

above, above, below, above, below, below

Hope this helps!

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The freezer is 18c after cooling the temp. Was -12c, what's the difference?

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I am pretty sure 30 is the answer

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3 years ago

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WhIich of the following mathematical expressions is equivalent to the verbal expression "A number, x, squared is 39 more than th

MrRa [10]

Answer:

E. x^2 = 39 + 10x

Step-by-step explanation:

It helps to do one piece of the sentence at a time.

"A number, x, squared is 39 more than the product of 10 and x"

"A number, x, squared is 39 more than the product of 10 and x"

x^2 =

"A number, x, squared is 39 more than the product of 10 and x"

x^2 = 39 +

"A number, x, squared is 39 more than the product of 10 and x"

x^2 = 39 + 10x

Answer: E. x^2 = 39 + 10x

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3 years ago

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Find the Volume. Use pi=3.14. Round to the nearest hundredth.

aleksandr82 [10.1K]

<h2>Volume = 4.19 inches³</h2>

<u>Step-by-step explanation:</u>

radius = 1 inches

π = 3.14

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= 4/3 × 3.14 × 1³

= 4.19 inches³

4 0

3 years ago

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

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3 years ago

Help plz will give brainliest

jolli1 [7]

Answer: 5(13.5-4.5)

5(9)

=45

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3 years ago