Answer:
26.8
Step-by-step explanation:
Because 33.5 was the average of how many students were in a classroom (if there were 4 classrooms), then 33.5 is can somewhat be the average of how many students were in one classroom; 1/4 of the classrooms can hold an average of 33.5.
Total students that were divided into 4 classrooms :
33.5 × 4 = 134
So if there is 134 students that will be grouped into 5 different classrooms, divide 134 by 5 to find the average amount of students that will be grouped.
134 ÷ 5 = 26.8
So, the average amount of students that will be grouped if they were divided into 5 classrooms would be 26.8 .
Hope this helped !
To find the volume of a cone you use the formula "1/3 x 3.14 x r^2 x h". Plug the formula into the problem. 1/3 x 3.14 x 3.75^2 x 3.5 =51.51. Rounded to the nearest tenth is 51.5. Hope this helps!
Answer:
B
Step-by-step explanation:
![P=2L+2W](https://tex.z-dn.net/?f=P%3D2L%2B2W)
(Subtract 2L from both sides of the equation)
(Symmetric Property of Equality)
(Divide both sides of the equation by 2)
("Split" the fractions)
(Simplify)
Hope this helps!
Alright then!
First off, is your picture REALLY necessary? Whatever haha
A mixed number is just a simplified fraction really.
16/3 = 5 1/3
Hope it helps!
Can you give me brainliest as well please? Thanks ~Samuel
Tables are easy to make when u have the equation. Just simply sub any number in for x and solve for y
y = 3x + 2...lets let x = 0
y = 3(0) + 2
y = 2.....so when x = 0, y = 2....(0,2)
y = 3x + 2....lets let x = 1
y = 3(1) + 2
y = 3 + 2
y = 5....so when x = 1, y = 5....(1,5)
y = 3x + 2.....let x = 2
y = 3(2) + 2
y = 6 + 2
y = 8....so when x = 2, y = 8...(2,8)
u can find more point if u need to...
now make a table..
x y
0 2
1 5
2 8
and like I said, if u need more numbers for ur table, just do like I did above :)