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zzz [600]
3 years ago
14

Which of the expressions below has a quotient that is greater than 15? Select all that apply.

Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0
The first one has a quotient greater than 15
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Find the common difference of the following sequence.​
Darya [45]

You have the correct answer. It is choice B) -1/4

=======================================================

Explanation:

This is because we're adding -1/4 to each term to get the next one. In other words, we're subtracting 1/4 from each term to get the next one.

  • term2 = term1+(d) = 1/2 + (-1/4) = 1/2 - 1/4 = 2/4 - 1/4 = 1/4
  • term3 = term2+(d) = 1/4 + (-1/4) = 1/4 - 1/4 = 0
  • term4 = term3+(d) = 0 + (-1/4) = 0 - 1/4 = -1/4
  • term5 = term4+(d) = -1/4 + (-1/4) = -2/4 = -1/2

and so on.

----------

To find the common difference, all we have to do is subtract any term from its previous one.

For example:

d = (term2) - (term1)

d = (1/4) - (1/2)

d = (1/4) - (2/4)

d = (1-2)/4

d = -1/4

The order of subtraction matters, so we cannot say d = term1-term2.

3 0
3 years ago
What is the slope of a line parallel to the line containing (-6,1) and (3,-2)
timama [110]

Answer:

m = -\frac{3}{9}

Step-by-step explanation:

Use the following formula:

slope: m = (y_{2} - y_{1})/(x_{2} - x_{1})

Let:

(x_{1} , y_{1}) = (-6 , 1)\\ (x_{2} , y_ {2}) = (3 , -2)\\

Plug in the corresponding numbers to the corresponding variables:

m = \frac{-2 - 1}{3 - (-6)}\\\\m = \frac{-3}{3 + 6}\\\\m = \frac{-3}{9}

m = -\frac{3}{9} is your answer.

~

3 0
4 years ago
A total of
Arte-miy333 [17]
Let x equal the number of adult tickets sold. 

X + 3X=512
(I put 3x because we know the students sold 3 times as many). 
Solve for X. 

X+3X=512
4X=512
4X/4=512/4
X=128
3 0
4 years ago
In a study on the time that
krok68 [10]

The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

-----------------------------

To solve this question, we need to find the confidence interval for the amount of time it takes the students to get the degree.

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

-----------------------------

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 80 - 1 = 79

-----------------------------

95% confidence interval

Standard level of confidence, we have to find a value of T, which is found looking at the t table, with 79 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9905.

-----------------------------

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9905\frac{2.2}{\sqrt{80}} = 0.5

In which s is the standard deviation of the sample and n is the size of the sample.

-----------------------------

The lower end of the interval is the sample mean subtracted by M. So it is 4.8 - 0.3 = 4.3 years.

The upper end of the interval is the sample mean added to M. So it is 4.8 + 0.3 = 5.3 years.

-----------------------------

The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

A similar question is given at brainly.com/question/24278748

6 0
3 years ago
The first four multiples of 7 are 7, 14 21, and 28. Use this example to help you as you answer the questions below.
Pachacha [2.7K]

Answer:

For A. it would be 9, 18, 27, 36, 45, 54

For B. it would be 12, 24, 36, 48, 60, 72

For C. it would be 36

For D. it would be 3

Step-by-step explanation:

Hope this helps

6 0
2 years ago
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