Start off by combining like terms on the LHS (the terms with x in them).
So we get
![\frac{-1}{3}x+2x= \frac{-1}{3}x+ \frac{6}{3}x= \frac{-5}{3}x](https://tex.z-dn.net/?f=%20%5Cfrac%7B-1%7D%7B3%7Dx%2B2x%3D%20%5Cfrac%7B-1%7D%7B3%7Dx%2B%20%5Cfrac%7B6%7D%7B3%7Dx%3D%20%5Cfrac%7B-5%7D%7B3%7Dx%20%20%20)
Replacing this result with what we had before on the LHS, we get
![\frac{-5}{3}x=3 \frac{3}{4}= \frac{9}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-5%7D%7B3%7Dx%3D3%20%5Cfrac%7B3%7D%7B4%7D%3D%20%5Cfrac%7B9%7D%7B4%7D%20%20%20)
⇒Solve for x (divide both sides
![\frac{-5}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-5%7D%7B3%7D%20)
)
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by
![\frac{3}{-5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B-5%7D%20)
⇒
![x= \frac{9}{4}( \frac{3}{-5}) ](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B9%7D%7B4%7D%28%20%5Cfrac%7B3%7D%7B-5%7D%29%0A%20%20)
⇒
![x= -\frac{27}{20}=-1\frac{7}{20}](https://tex.z-dn.net/?f=x%3D%20-%5Cfrac%7B27%7D%7B20%7D%3D-1%5Cfrac%7B7%7D%7B20%7D)
***This is a proper fraction
Answer:
<h2>m∠LMN = 26°</h2>
Step-by-step explanation:
Since ∠LMN and ∠PQR are complementary it means that the sum of their angles is 90°
To find m∠LMN , add both m∠LMN and m∠PQR and equate it to 90 to find x then substitute the value of x into the expression for m∠LMN
That's
m∠LMN + m∠PQR = 90
4x - 2 + 9x + 1 = 90
13x - 1 = 90
13x = 90 + 1
13x = 91
Divide both sides by 13
x = 7
From the question
m∠LMN = (4x-2)
m∠LMN = 4(7) - 2 = 28 - 2
We have the final answer as
<h3>m∠LMN = 26°</h3>
Hope this helps you
Answer:
24m -32
Step-by-step explanation:
8(3m-4)
8(3m)-8(4)
8(3m)=24m
24m-8(4)
8(4)=32
Answer:
2
Step-by-step explana
(6x-y+4)*2= 12x -2y+8= (3x+9x)-(2y-8)