Answer:
C and D
Step-by-step explanation:
1
The arc length is calculated as
arc = circumference of circle × fraction of circle
= 2πr × 
= 2π × 10 ×
=
=
cm → C
-----------------------------------------------------
2
The area (A) of a sector is calculated as
A = area of circle × fraction of circle
= πr² × 
= π × 10² ×
=
=
cm² → D
Answer:
hey here's your answer!☺️
since number = n
so, 5 times of number = 5×n = 5n
and , 30 more than 8 times the number = 8n + 30
so, According to the question,
equation formed :-
" 5n = 8n + 30 "
hope it is helpful ✌️!
Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2
This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that
g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2
So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).
Here's proof of both claims
-----------------------------------------
Proof of Claim 1:
f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6
-----------------------------------------
Proof of Claim 2:
h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2
The probability of rolling any specific number is 1/6. The expected number of points is found from:
E(points) = (1/6 * -1) + (1/6 * -2) + (1/6 * -3) + (1/6 * 4) + (1/6 * 5) + (1/6 * 6)
= 9/6 = 1.5 points
Answer:
The area of the regular octagon is 
Step-by-step explanation:
we know that
The area of the regular polygon is equal to

where
P is the perimeter of the regular polygon
a is the apothem
<em>Find the perimeter P</em>

Find the area
