Find each sum.
1. 56+ (-56) = 0
The number series 1, 2, 3, 4, 55, 56. Therefore, 1596 is the sum of positive integers.
Option A
The restaurant Manager can afford at most 10 employees for the day
<em><u>Solution:</u></em>
Given that restaurant manager can spend at most $600 a day for operating costs and payroll
It costs $100 each day to operate the bank and $50 dollars a day for each employee
The given inequality is:

Where , "x" is the number of employees per day
Let us solve the inequality for "x"

Add -100 on both sides of inequality

Divide by 50 on both sides of inequality

Hence the restaurant Manager can afford at most 10 employees for the day
Thus option A is correct
Answer:
Money raised by each team = 94 + 11 = <em>$105</em>
Number of cars washed = <em>11</em>
Step-by-step explanation:
Money already present with volleyball team = $50
Money raised by washing each car by volleyball team = $5
Let the number of cars washed =
Money raised by washing cars = $5
Money already present with volleyball team = $94
Money raised by washing each car by volleyball team = $1
Money raised by washing cars = $1
= $
Given that, both the teams have raised same amount of money:

Money raised by each team = 94 + 11 = <em>$105</em>
Number of cars washed = <em>11</em>
Answer:
3.42
Step-by-step explanation:
41/12 is 3.42
6.2:
fraction: .2 = 0.20 = 20/100
fraction: 6 20/100
Word form: six point two
two and five hundredths
fraction: 2 5/100
decimal form 2.05
hope this helps