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Hoochie [10]
4 years ago
8

Dividing my dog’s age by 4 and adding 6 is the same as dividing my dog’s age by 8 and adding 8.

Mathematics
2 answers:
Alenkinab [10]4 years ago
6 0
I don’t understand what the is question
Delvig [45]4 years ago
5 0

Answer:

16

Step-by-step explanation: its just a guess but i got it right

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It takes 2 minutes to print 3 photos. AT this rate, how many minutes will it take to print 10 photos?
vitfil [10]
It would take 15 minutes to print 10 photos
3 0
3 years ago
9/3
hjlf

Answer:

$960

Step-by-step explanation:

Given data

Principal=$800

rate= 4%

time= 5years

Applying the compound interest expression we have]

A=P(1+rt)

substitute

A=800(1+0.04*5)

A=800(1+0.2)

A=800*1.2

A=$960

8 0
3 years ago
3.49 hectograms equals how many decigrams​
klasskru [66]

Answer:

3490 decigram

Step-by-step explanation:

1 \:hectogram = 1000 \:decigram\\\\3.49\: hectogram = x\: decigram\\\\Cross\:Muliply\\\\x = 3.49\times 1000\\\\x = 3490 \:decigram

8 0
4 years ago
Consider the graph of f(x) below. The graph contains the points (0, 1) and (5, 4).
12345 [234]

y= (3/5)x-1    exponetial

i am not a 100% on this

8 0
3 years ago
Problem: Suppose that on-the-job injuries in textile mill occur at the rate of 0.1 per day. What is the probability that two acc
sertanlavr [38]

Answer: the probability that two accidents will occur during the (five-day) work week is 0.0758

Step-by-step explanation:

Given that;

injuries in textile mill occur at the rate of 0.1 per day; λ = 0.1

probability that two accidents will occur during the (five-day) work week = ?

T= 5

so, the average number of on the job injuries for five days will be;

λT = 0.1 × 5

= 0.5

now if X follows Poisson distribution, hemce

P( X=k ) = [e^-λT (λT)^k] / k!

so the probability that two (2) accidents will occur during the (five-day) work week will be;

P( X=k ) = [e^-0.5 (0.5)²] / 2!

= (0.6065 × 0.25) / 2

= 0.1516/ 2

= 0.0758

the probability that two accidents will occur during the (five-day) work week is 0.0758

3 0
3 years ago
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