If the triangle has a angle of 90°, you can solved this exercise by applying the Pythagorean Theorem, which is:
h²=a²+b²
h=√(a²+b²)
h: It is the hypotenuse
(The opposite side of the right angle and the longest side of the triangle).
a and b: They are the legs
(The sides that form the right angle).
The result of h=√(a²+b²), should be 17.1 (The longest side given in the problem). So, let's substitute the values of the legs into the Pythagorean equation:
h=√(a²+b²)
h=√((9.2)²+(14.5)²)
h=17.1
Therefore, the answer is:
Yes, the given measures can be the lengths of the sides of a triangle.
Answer:
b) 105°
d) 130°
Step-by-step explanation:
An external angle has the same measure as the sum of the remote internal angles.
b) ? = 25° +80° = 105°
d) ? = 35° +95° = 130°
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This should be fairly obvious if you consider that the adjacent internal angle together with the external angle totals 180°, and the adjacent internal angle together with the other two internal angles totals 180°.
If the two "remote" angles are A and B, and the adjacent internal angle is C, then we have in symbols ...
A + B + C = 180° = ? + C
If we subtract C, then we find ...
A + B = ? . . . . . . the fact we used above
The actual speed of the plane with the wind:
v² = ( 150 + 50 · cos 45°)² + ( 50 · sin 45°)²
v² = ( 150 + 35.355 )² + 35.355²
v² = 34,356.467 + 1,249.976
v = √35,606.452
v = 188.7 mph
I believe it to be six but than again I could be sadly wrong
Your question seems incomplete
is there an image supposed to be attached to it
