120/143. 12 x 10 is 120, and 13 x 11 is 143. It is already in simplest form.
13. if edward wins 6 of his remaining games...that would make a total of 12 wins (since he already won 6 earlier)
3/4 as many winsa as edward....3/4(12) = 36/4 = 9...so he would have to win 9 to have 3/4's as much as edward...and howard has already won 4...so he needs (9 - 4) = 5....he needs 5 wins
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14. Robert has already won 2, and he has lost 8...so he would have to win at least 7 of his games to have more wins then losses
Answer:
Step-by-step explanation:
EASy
Substitute in the values and solve.
1) B
For A:
3 = 4(1)
<u>This is NOT true.</u>
For B:
-4 = 4(-1)
<u>This IS true.</u>
For C:
-1 = 4(-4)
<u>This is NOT true.</u>
For D:
-4 = 4(1)
<u>This is NOT true.</u>
2) None. Possible solutions: (0,2) (1,-5)
For A:
2 = -7(1) + 2
2 = -7 + 2
<u>This is NOT true.</u>
For B:
-52 = -7(8) + 2
-52 = -56 + 2
<u>This is NOT true.</u>
For C:
-35 = -7(5) + 2
-35 = -35 + 2
<u>This is NOT true.</u>
For D:
-7 = -7(1) + 2
-7 = -7 + 2
<u>This is NOT true.</u>
Answer:
=28
Step-by-step explanation:
3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4
3 (20-4) -4 ( 12 - 7)
60 - 12 -48 +28
= 28
