-6+2x=14 what are the steps to do these

Find the perimeter of a regular pentagon with sides of (3x + 5).

kotegsom [21]

Answer:

5(3x + 5) or 15x + 25

Step-by-step explanation:

A regular pentagon has 5 sides of equal length. The perimeter is the sum of the lengths of those sides. We can use multiplication to find the sum of 5 of the same value:

P = 5(3x +5)

Perhaps you want it expanded. Using the distributive property, we multiply each term in parentheses by 5:

P = 15x + 25

4 0

4 years ago

HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER

NeTakaya

Step-by-step explanation:

x=90°

SUM OF ALL ANGLES OF PENTAGON =540

90+2(180-Y)+105+113=540

90+360-2Y+105+113=540

488-2Y=540

7 0

3 years ago

Read 2 more answers

A sphere has a radius of 11 feet. A second sphere has a radius of 8 feet. what is the difference of the volume of thespheres

Veronika [31]

The difference between the volume of the spheres is 3428.88 cubic feet

Explanation:

Given that one sphere has a radius of 11 feet.

A second sphere has a radius of 8 feet.

Volume of the 1st sphere:

The formula to determine the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Volume of the 1st sphere is given by

$V=\frac{4}{3}(3.14)(11)^3$

$V=\frac{4}{3}(3.14)(1331)$

$V=\frac{16717.36}{3}$

$V=5572.45$

The volume of the 1st sphere is 5572.45 cubic feet.

Volume of the 2nd sphere:

Volume of the 2nd sphere is given by

$V=\frac{4}{3}(3.14)(8)^3$

$V=\frac{4}{3}(3.14)(512)$

$V=\frac{6430.72}{3}$

$V=2143.57$

The volume of the 2nd sphere is 2143.57 cubic feet.

Difference between the volume of the two spheres:

Difference = Volume of the 1st sphere - Volume of the 2nd sphere

= 5572.45 - 2143.57

Difference = 3428.88 cubic feet.

Hence, the difference between the volume of the spheres is 3428.88 cubic feet.

7 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

$EV=\lambda*t=5*0.75=3.75$

8 0

3 years ago

Two pieces of lengths 13/3 m and 3/5 m are cut off from a rope 15

garri49 [273]

Hello there! ;) The way you solve this type of problem is you must find common denominators. So simplify 13/3= 4 1/3. So we can do 1/3*5/5=5/15. Next we must do 3/5*3/3= 9/15. So add 5/15+9/15= 14/15. And add the 4+ 14/15= 4 14/15. So then you must subtract 15 - 4 14/15= 10 1/15 I believe. I believe 10 1/15 is the remainder of the rope. You might want to check in with someone else though.

Hope I help! :D

5 0

4 years ago