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FromTheMoon [43]
3 years ago
11

The population of a city is decreasing by 4.5% each year. The population in the year 2010 started at 8,000 people. Make a table

to represent how many years it would take to reach 3000 people.
Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

log(.375)/log(.955) = x

Step-by-step explanation:

To decrease by 4.5% means you multily by 1-.045 or .955.  It might be easier to see if you write it as 8000 - 8000 * .045.  Either way, now you can write it as 8000*.955.

Now, if this happened again you would multiply by .955 twice, or in other words have 8000 * .955^2.  You can keep going with this, which shows you can make this an exponential function.  8000*.955^x where x is the number of years the population decreases by 4.5%

The question then says how many times would we hae to decrease by 4.5% to get to 3000.  One way to do this is try every x value until you get there.  That usually takes a long time, so instead we use logs.

If you don't understand logs let me know, but basically it takes exponential functions and turns them into something else.  specificlaly it takes a = b^x where a and b are just numbers and x is the exponent, and turns it into log_b(a) = x or log base b of a equals x.  This will let us solve for x as a variable.  

To enter this into a calculator jut use log(a)/log(b) or ln(a)/ln(b).

Anyway, we start with 3000 = 8000*.955^x  That's not quite what we need to start with so divide both sides by 8000

3000/8000 = .955^x

3/8 = .955^x

.375 = .955^x

Then turn it into logarithmic form

log_.955(.375) = x

then just solve with the method I showed

log(.375)/log(.955) = x

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solong [7]

Answer:

(x+4)^2+(y-6)^2=81

Step-by-step explanation:

We want to find equation of a circle with center (-4,6) and radius 9cm.

The equation of a circle with center (h,k) and radius r units is given by;

(x-h)^2+(y-k)^2=r^2

We substitute the radius and the center to obtain;

(x+4)^2+(y-6)^2=9^2

The required equation is:

(x+4)^2+(y-6)^2=81

3 0
3 years ago
What is the simplified form of the equation fraction 4 over 5 n minus fraction 1 over 5 equals fraction 2 over 5 n?
Umnica [9.8K]

Answer:

n=2

Step-by-step explanation:

⁴/5n-¹/5=²/5n

first we remove the denominators by multiplying all the numbers with their lcm

Lcm of 5n and 5 is 5n thus:

(5n×⁴/5n)-(¹/5×5n)=²/5n×5n

4-n=2

4-2=n

n=2

<h3>confirmation</h3>

insert 2 insted of n

⁴/5(2)-¹/5=²/5(2)

⁴/10-¹/5=²/10. simplify

²/5-¹/5=¹/5

¹/5=¹/5

so the correct value of n is 2

6 0
3 years ago
6r +9r - 2r - 13n combine like terms.
kolbaska11 [484]

Answer:

13r-13n

Step-by-step explanation:

just add 9r+6r get 15r then subtract it by 2r then you get 13r and you can't subtract unlike terms

8 0
3 years ago
Read 2 more answers
The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St
AysviL [449]

Answer:

a) 0.0668 = 6.68% probability that a domestic airfare is $550 or more

b) 0.1093 = 10.93% probability than a domestic airfare is $250 or less

c) 0.6313 = 63.13% probability that a domestic airfare is between $300 and $500

d) The cost for the 3% highest domestic airfares are $592 and higher.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 385, \sigma = 110

a. What is the probability that a domestic airfare is $550 or more (to 4 decimals)?

This is 1 subtracted by the pvalue of Z when X = 550. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 385}{110}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that a domestic airfare is $550 or more

b. What is the probability than a domestic airfare is $250 or less (to 4 decimals)?

This is the pvalue of Z when X = 250. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{250 - 385}{110}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093

0.1093 = 10.93% probability than a domestic airfare is $250 or less

c. What if the probability that a domestic airfare is between $300 and $500 (to 4 decimals)?

This is the pvalue of Z when X = 500 subtracted by the pvalue of Z when X = 300. So

X = 500

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 385}{110}

Z = 1.045

Z = 1.045 has a pvalue of 0.8519

X = 300

Z = \frac{X - \mu}{\sigma}

Z = \frac{300 - 385}{110}

Z = -0.77

Z = -0.77 has a pvalue of 0.2206

0.8519 - 0.2206 = 0.6313

0.6313 = 63.13% probability that a domestic airfare is between $300 and $500

d. What is the cost for the 3% highest domestic airfares?

At least the 97th percentile, so at least X when Z has a pvalue of 0.97. So X when Z = 1.88.

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 385}{110}

X - 385 = 1.88*110

X = 592

The cost for the 3% highest domestic airfares are $592 and higher.

7 0
3 years ago
Simplify.<br><br> [3 • (3 – 9)] + 9
Marat540 [252]

Answer:

(9-27)+9

=-18+9

<em><u>=-9</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em>

4 0
3 years ago
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