Answer: y=40x+100
Step-by-step explanation: it’s growing by 40 every week so x=number of weeks and 100 is the starting point so you always add that. Ex) week 3: 40(3)+100 = 120+100=220
Answer:
$0 < p ≤ $25
Step-by-step explanation:
We know that coach Rivas can spend up to $750 on 30 swimsuits.
This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:
C ≤ $750
Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:
C = 30*p
Then we have the inequality:
30*p ≤ $750.
To find the possible values of p, we just need to isolate p in one side of the inequality.
So we can divide both sides by 30 to get:
(30*p)/30 ≤ $750/30
p ≤ $25
And we also should add the restriction:
$0 < p ≤ $25
Because a swimsuit can not cost 0 dollars or less than that.
Then the inequality that represents the possible values of p is:
$0 < p ≤ $25
Answer:
Figure A
Step-by-step explanation:
Hope it helps.
387000 times 0.29 <--- (same as 29%)
=112230 (this is the increased value aka the 29%)
387000-112230=274770 (subtracting to find original value)
Answer is $274,770