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AlladinOne [14]
3 years ago
9

What is 0.008 simple lest form

Mathematics
2 answers:
horsena [70]3 years ago
8 0
0.008 is 8/1000 = 4/500 = 2/250 = 1/125
Hatshy [7]3 years ago
3 0
<span>Step 1: 0.008 = 8⁄1000</span>
<span>Step 2: Simplify 8⁄1000 = 1⁄125</span>             
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im not sure wether to replace the minus signs with addition, so if you could help me that would be nice :) 1.2y+4.5-3.4y-6.3
Elenna [48]

Answer:

-2.2y - 1.8

Step-by-step explanation:

We are to simplify the expression:

1.2y + 4.5 - 3.4y - 6.3

Collect like terms:

1.2y - 3.4y + 4.5 - 6.3

Simplify:

-2.2y - 1.8

That is the answer.

6 0
3 years ago
What is the square root of 70 million
lutik1710 [3]
The square root of 70 millions is <span>8366.60026534</span>
8 0
3 years ago
Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217
Soloha48 [4]

Answer:

f(216) \approx 6.0093

Step-by-step explanation:

Given

\sqrt[3]{217}

Required

Solve

Linear approximated as:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

Take:

x = 216; \triangle x= 1

So:

f(x) = \sqrt[3]{x}

Substitute 216 for x

f(x) = \sqrt[3]{216}

f(x) = 6

So, we have:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

f(215 + 1) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot f'(x)

To calculate f'(x);

We have:

f(x) = \sqrt[3]{x}

Rewrite as:

f(x) = x^\frac{1}{3}

Differentiate

f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}

Split

f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}

f'(x) = \frac{x^\frac{1}{3}}{3x}

Substitute 216 for x

f'(216) = \frac{216^\frac{1}{3}}{3*216}

f'(216) = \frac{6}{648}

f'(216) = \frac{3}{324}

So:

f(216) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot \frac{3}{324}

f(216) \approx 6  + \frac{3}{324}

f(216) \approx 6  + 0.0093

f(216) \approx 6.0093

6 0
3 years ago
Let X and Y be the following sets:
melisa1 [442]
Give me brainlist Djjdksodood
8 0
3 years ago
The diameter of a circle is 8 feet. What is the angle measure of an arc a feet long?
fiasKO [112]

Answer:

Given: circle

diameter = 10 cm => radius (R) = 5 cm

Find: measure of angle bounding sector = 11 π sq. cm.

Plan: determine what part of the circle’s total area equals the sector’s area.

Total Area of Circle A = π R^2 = π 5^2 = 25 π sq. cm.

Therefore: Sector Area = 11 π cm^2/25 π cm^2 = 11/25

Since the sector is 11/25 th of the circles area, the sector angle will measure 11/25 th of the circle’s circumference. They are proportional.

C = 2 π R = 2 π (5) = 10 π cm

Sector Arc = measure of sector angle = 11/25 (10 π) =

22π/5 radians

Answer: Sector Arc = 22π/5 Radians

4 0
2 years ago
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