You seem to have forgotten to add in the y-intercept or slope. For the information you have given, it could be any equation, so long as it passes through the point (2, -1), such as
y = -x + 1
Answer: 3x^4 +x^3 -2x^2 +3x +2
Step-by-step explanation:
(3x^4 - 2x^3 + 4x -2) + (3x^3 - 2x^2 - x +4)
There are no like terms for 3x^4, so leave it alone.
-2x^3 + 3x^3 = 1x^3
No like terms for -2x^2
4x - x = 3x
-2 + 4 = 2
Answer? 3x^4 +x^3 -2x^2 +3x +2
(Please mark brainliest! :) )
Answer:
Step-by-step explanation:
The function for this problem is: h(t) = -16(t)^2 + vt + s h= the height t= time v= velocity s= starting height With the information given, we know that the starting height is 0, since it was from the ground, and the velocity of the ball is 35 feet per second. Inserting the these information into the equation, we get: h(t) = -16(t)^2 + 35t Now the question asks to find the maximum height. It can be done by using a grapher to graph the maximum of the parabola. It could also be done by finding the vertex, which would be the maximum, of the graph by using x= -b/(2a), where b is equal to 35 and a is equal to -16. We get x=35/32, the x-value of where the vertex lies. You can use this value as the t-value in the previous equation to find the h-value of the vertex. When you do, you get h= 19.1 feet, or answer D.
hope this helps
Answer: 11
<u>Step-by-step explanation:</u>
125 passengers ÷ 12 passengers/trip = 10.4 trips
Round UP to make sure every passenger arrives → 11 trips
