Answer:
Step-by-step explanation:
We have that
A = 51°, b = 14, c = 6
step 1
find the value of a
Applying the law of cosines
a²=c²+b²-2*c*b*cos A
a²=6²+14²-2*6*14*cos 51-------> 126.27
a=11.2
we know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
we have
a=11.2
b=14
c=6
so
(a+b) > c-------------> (11.2+14)=25.2
25.2 > 6-----> is not correct
therefore
the answer is the option
a. No triangles possible
I don't know if i am right sorry if this is wrong
I think it's one of the last 2 they equal the same thing, so -8+(-3) is the answer.
Step-by-step explanation:
Just think of these as your building blocks for geometry success.
Diagram for success. ...
Know your properties and theorems.
Understand Euclid's postulates.
Learn the language of math.
Know your angles. ...
Know your triangles. ...
Figure out what you want and what you're given. ...
Now fill in the rest.
Look up Quadratic Formula Pop Goes the Weasel
its like 30 seconds and is pretty easy to remember
Your answers are wrong. the function f(x) is like a factory. you put in something ( a number) and it will spit you out something else (a different number depending on the function). your function, f (x)= -2x+1
you can put anything in that function. let say k.
f(x=k) = -2k+1. you just replace the x with k.
in this particular problem they way f(-2) ,f(0), f(1) and f(2).
here are the results
f(x=-2) = f(-2) = -2×(-2)+1 =5
f(x=0) = f(0) = -2×(0)+1 =1
f(x=1) = f(1) = -2×(1)+1 =-1
f(x=2) = f(2) = -2×(2)+1 =-3
