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Kamila [148]
3 years ago
6

0.3643 in scientific notation

Mathematics
2 answers:
Radda [10]3 years ago
8 0

Answer:

             -1

3.643*10

Step-by-step explanation:

move the decimal

lord [1]3 years ago
7 0
3.643 x 10^-1 would be the answer
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Determine the values of a for which the following system of linear equations has no solutions, a unique solution, or infinitely
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Answer:

Never

Never

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Step-by-step explanation:

The equations given are

2x1−6x2−4x3 = 6 ....... (1)

−x1+ax2+4x3 = −1 ........(2)

2x1−5x2−2x3 = 9 ..........(3)

the values of a for which the system of linear equations has no solutions

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.

a unique solution,

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

The value of a = never

infinitely many solutions. 

Divide equation 1 by 2 we will get

X1 - 3X2 - 2X3 =3

Add the above equation with equation 3. This will result to

3X1 - 8X2 - 4X3 = 12

Everything ought to be the same. Since they're not.

Value of a = never.

4 0
3 years ago
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Step-by-step explanation:

(-2, y) = (x, y)

y = 3^x

y = 3^(-2)

y = 1/9

Therefore y = 1/9
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