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Kamila [148]
3 years ago
6

0.3643 in scientific notation

Mathematics
2 answers:
Radda [10]3 years ago
8 0

Answer:

             -1

3.643*10

Step-by-step explanation:

move the decimal

lord [1]3 years ago
7 0
3.643 x 10^-1 would be the answer
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If a gas tank of a large truck holds 64 gallons of gas if the tank is 5/8 full how many gallons of gas is in truck
den301095 [7]
Find 5/8 of full
find 5/8 of 64
5/8 times 64/1=320/8=160/4=80/2=40
answer is 40 gallons in the trick right now
4 0
3 years ago
Determine+the+percentile+indicating+the+bottom+ranking+20%.+in+other+words,+what+is+the+dollar+number+that+defines+where+the+low
Aloiza [94]

The dollar number that defines where the lowest values falls is

20% percentile value =$20

This is further explained below.

<h3 /><h3>What is the dollar number that defines where the lowest value falls?</h3>

Generally,  Now we need to determine the 20th percentile ($20). It indicates that we need to locate a dollar amount that marks the point at which the 20 % data has a value lower than that number.

i=(p/100)*n

Where i is the position of p^th

percentile when the data is presented in ascending order.

i=20/100*50

i=1000/100

i=10

Therefore

n=50

p=20

In conclusion, the 10th position for given data is 20,

Therefore, 20% percentile value =$20

Read more about percentile

brainly.com/question/1594020

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5 0
2 years ago
Someone please help!
Sloan [31]

Answer:

plot the points & find where they insect then calculate the mid-point

4 0
3 years ago
Read 2 more answers
Solve for n.<br><br> 2n-3/5 = 5.
dangina [55]

\dfrac{2n-3}{5}=5\\\\&#10;2n-3=25\\\\&#10;2n=28\\\\&#10;n=14

7 0
3 years ago
The following data show the midterm and final exam scores in an English writing class. Student 1 2 3 4 5 6 7 8 9 10 11 12 Midter
tester [92]

Answer:

The co variance of the midterm and final exam scores is 58.76.

Step-by-step explanation:

The formula to compute the sample co variance is:

Cov(x,y)=\frac{\sum(X-Mean\ of\ X)(Y-Mean\ of\ Y)}{n-1}

The values are computed in the table below.

Compute the co variance as follows:

Cov(x,y)=\frac{\sum(X-Mean\ of\ X)(Y-Mean\ of\ Y)}{n-1}\\=\frac{646.33}{12-1}\\ =58.76

Thus, the co variance of the midterm and final exam scores is 58.76.

7 0
3 years ago
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