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Alexxandr [17]
3 years ago
5

Help meeee it's math ::Simplify an expression for the perimeter of the rectangle shown

Mathematics
1 answer:
bagirrra123 [75]3 years ago
5 0
8.6x + 3 + 8.6+3 =. 17.2x + 6


5.2+5.2= 10.4

17.2x + 6 = 10.4
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If f(x) = x2 – 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?
Hatshy [7]

Answer:

x = - 2

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= x² - 2x + 6x + 4

= x² + 4x + 4

Equating to zero

x² + 4x + 4 = 0

(x + 2)² = 0

x + 2 = 0

x = - 2

6 0
2 years ago
Hey guys does anyone know how to lesson 26 Exit ticket 5.4 eureka math engage ny? The last problem: Larry spends half of his wor
Vesnalui [34]

Answer:

\frac{1}{12}X

Step-by-step explanation:

Let X is the number of hours Larry works a day

Given:  Larry spends half of his workday teaching piano lessons.

=> Number of hours he teaches piano a day is: \frac{1}{2}X

As we know that, he has 6 students, so the fraction of his workday is spent with each student is:

\frac{1}{2}X : 6

= \frac{1}{12}X

Hope it will find you well during the time of isolation.

7 0
3 years ago
Read 2 more answers
Which is the solution of x=2+√x-2? <br>x=2 <br>x=3 <br>x=2 or x=3 <br>no solution​
erik [133]
No Solution
x=2+ Square root of x-2
-2
x-2= Square root of x-2
2s cancel out.
x = Square root of x
Or you can just graph it and see no solutions
6 0
3 years ago
Which point is on the graph of f(x) = 2*5^x
vodomira [7]

Answer:

Option B (1,10)

Step-by-step explanation:

we have

f(x)=2(5^x)

we know that

If a ordered pair is on the graph of f(x) then the ordered pair must satisfy the function f(x)

<u><em>Verify each case</em></u>

case A) (0,0)

For x=0

f(x)=2(5^0)\\f(x)=2(1)=2

Compare the value of f(x) with the y-coordinate of the ordered pair

2\neq 0

therefore

The ordered pair is not on the graph of f(x)

case B) (1,10)

For x=1

f(x)=2(5^1)\\f(x)=2(5)=10    

Compare the value of f(x) with the y-coordinate of the ordered pair

10=10

therefore

The ordered pair is on the graph of f(x)

case C) (0,10)

For x=0

f(x)=2(5^0)\\f(x)=2(1)=2

Compare the value of f(x) with the y-coordinate of the ordered pair

2\neq 10

therefore

The ordered pair is not on the graph of f(x)

case D) (10,1)

For x=10

f(x)=2(5^{10})\\f(x)=2(9,765,625)=19,531,250

Compare the value of f(x) with the y-coordinate of the ordered pair

19,531,250\neq 1

therefore

The ordered pair is not on the graph of f(x)

7 0
3 years ago
2/5 times 17<br> WHOEVER ANSWERS FIRST I GIVE BRAINY!
ikadub [295]

Answer:

6.8

Step-by-step explanation:

(2/5)*17

=6.8

5 0
3 years ago
Read 2 more answers
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