F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Answer:
x>-6
Step-by-step explanation:
The expression you need to solve for this is: 2x+15>3
For now pretend that the > is a = and solve as you normally would for x.
Subtract 15 from both sides
2x=-12
Divide by 2
x=-6
Put the > back in
x>-6

- Increase = 20 - 15 = 5 points
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