3 years ago

A dice is tossed 3 times. Let X be the sum of the 3 numbers obtained

Mathematics

1 answer:

UNO [17]3 years ago

4 0

X + 3 (3) will be the answer

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La razon de 3 librasa $ 6.00

andrew-mc [135]

Answer:

I would love to help you so much but I don't understand

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3 years ago

The average number of points a basketball team scored for three games was 63 points. In the first two games they scored the same

Jobisdone [24]

Answer:

3rd game: 59 The other 2 games 65 each

Step-by-step explanation:

(x+6)+(x+6)+x:3=63

Multiply all by 3

3x+12=189

3x= 177

x=59 (3rd=59 The other 2 65 each

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3 years ago

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2(x-3)+5>39<br><br><br> Please explain how to get it!

ollegr [7]

Answer: x > 20

Step-by-step explanation:

first, i removed the parentheses.

2x - 6 + 5 > 39

then i calculated it.

2x - 1 > 39

then, i moved the constant to the right.

2x > 39 + 1

then, i added the two.

2x > 40

finally, i divided both sides.

solution: x > 20

8 0

3 years ago

Read 2 more answers

If the substitution u=x/2 is made, the intergal from 2 to 4 1-(x/2)^2/x dx =

stich3 [128]

$\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx$

Setting $u=\dfrac x2$ gives $\mathrm du=\dfrac{\mathrm dx}2$ , or $2\,\mathrm du=\mathrm dx$ . This also makes $2u=x$ .

When $x\to2^+$ , you have $u\to\dfrac22=1$ , while when $x\to4^-$ , you have $u\to\dfrac42=2$ .

Putting everything together, you find that

$\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx=\int_1^2\frac{1-u^2}{2u}(2\,\mathrm du)=\int_1^2\frac{1-u^2}u\,\mathrm du$

which means (B) is the correct answer.

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3 years ago

Help my this problem

Inga [223]

Answer:

-2

Step-by-step explanation:

Please view the image I have provided.

7 0

3 years ago