Answer:
x=4
Step-by-step explanation:
13x+1 = 11x+9
13x-11x = 9-1
2x = 8
x = 4
Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
Let's solve your equation step-by-step.
6.75+38x=1314
Step 1: Simplify both sides of the equation.
38x+6.75=534
Step 2: Subtract 6.75 from both sides.
38x+6.75−6.75=534−6.75
38x=132
Step 3: Multiply both sides by 8/3.
(83)*(38x)=(83)*(132)
x=523
Answer:
x=1713
Answer:
1. C) 3
2. D) -1
3. D) 7^2 - 8*2 - 16
4. B) 75
5. B) 6^2 + (2 - 8)*sqrt(81)
Step-by-step explanation:
1. (10 - (6-4)^2)/2
= (10 - 2^2)/2
= (10 - 4)/2
= 6/2
= 3
2. PEMDAS states that Multiplication is before Subtraction
8 - (5^2-7)/2
= 8 - (25-7)/2
= 8 - 18/2
= 8 - 9
= -1
3. D) 7^2 - (8*2) - 16
= 49 - 16 - 16
= 49 - 32
= 17
4. 3(2 + 3)^2
= 3(5)^2
= 3(25)
= 75
5. 6^2 + (2 - 8)*sqrt(81)
= 36 + (-6*9)
= 36 - 54
= -18
10.0.0.0/8 is variably subnetted, 3 subnets, 2 masksC10.1.1.0/30 is directly connected, Serial0/0/0L10.1.1.1/32 is directly connected, Serial0/0/0R10.2.2.0/30 [120/1] via 10.1.1.2, 00:00:21, Serial0/0/0172.30.0.0/16 is variably subnetted, 2 subnets, 2 masksC172.30.10.0/24 is directly connected, GigabitEthernet0/1L172.30.10.1/32 is directly connected, GigabitEthernet0/1R3 only displays its own subnets for the 172.30.0.0 network. R3 does not have any routes for the172.30.0.0 subnets on R1.
