Foactoring Diff/ Sum of Cubes Factor completely
1 answer:
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Answer:
1
Step-by-step explanation:
Using the definition
n =
where n! = n(n - 1)(n - 2) × 3 × 2 × 1
and 0! = 1
3
=
=
= = 1
Answer:
1
Step-by-step explanation:
Using the definition
n =
where n! = n(n - 1)(n - 2) × 3 × 2 × 1
and 0! = 1
3
=
=
= = 1