All categories

3 years ago

Given that (-5,-8) is on the graph of f(x), find

Mathematics

1 answer:

Fofino [41]3 years ago

8 0

Answer:

can u give more information than i will answer

Step-by-step explanation:

You might be interested in

A dealer sold 500 tennis racquets some were sold at $20 each and the rest were sold at $45 each. The total receipts from these s

arlik [135]

Answer:

He sold 100 rackets for $ 20

Step-by-step explanation:

To start, we have to make 2 equations, one that represents the number of rackets and the other the money

x + y = 500

x * 20 + y * 45 = 20000

we clear x in the first equation

x + y = 500

x = 500 - y

we replace x in the second equation with (500 - y)

x * 20 + y * 45 = 20000

(500 - y) * 20 + y * 45 = 20000

10000 - 20y + 45y = 20000

-20y + 45y = 20000 - 10000

25y = 10000

y = 10000/25

y = 400

we replace x in the first equation with the value obtained

x = 500 - y

x = 500 - 400

x = 100

He sold 100 rackets for $ 20

8 0

3 years ago

Read 2 more answers

marcela's dog gained 4.1 kilograms in two months. two months aga the dog's mass was 5.6 kilograms. what is the dog's current mas

Oksana_A [137]

5.6+4.1=9.7 The dog is now 9.7 kg.

6 0

3 years ago

Read 2 more answers

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

5 0

3 years ago

If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ?

Dominik [7]

Answer:

$HJ=20\ units$

Step-by-step explanation:

The complete question is

RT and GJ are chords that intersect at point H. If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ? 18 units 20 units 26 units 28 units

we know that

The intersecting chords theorem is a statement that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal

In this problem

$(RH)(HT)=(GH)(HJ)$

substitute the given values

$(10)(16)=(8)(HJ)$

solve for HJ

$HJ=160/8\\HJ=20\ units$

7 0

3 years ago

Read 2 more answers

The graph below shows the distance, y, in miles, of a bird from its nest for a certain amount of time, x, in minutes:

Montano1993 [528]

Answer:

$0.2$ miles per minute represents the speed of the bird and 3 miles represents the original distance of the bird from its nest.

Step-by-step explanation:

As there is no graph mentioned here but the information are quite sufficient to answer the question.

We have points $(0,3), (5,4),(10,5)...$

From these points we can find the slope of the line .

From point slope formula $y-y_1=m(x-x_1)$

And assigning $(x,y) (0,3)$ and $(x_1,y_1) (5,4)$

$m=\frac{y_1-y}{x_1-x} =\frac{4-3}{5-0} =\frac{1}{5}=0.2$

This slope is also the speed of the bird which is $0.2\ miles\ per\ minute.$

As by plugging the values of any coordinate point we can confirm this.

Lets put $(10,5)$ , y-axis is the distance so in $10$ minutes the the distance covered by the bird must be equal to to y-axis value which is $5$ miles.