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Alex_Xolod [135]
3 years ago
13

Given that (-5,-8) is on the graph of f(x), find

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

can u give more information than i will answer

Step-by-step explanation:

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Find the 18th term of the arithmetic sequence whose common difference is d=5 and whose first term is a, = 4.
dedylja [7]

Answer: 89

the 18th term is 4 + (18 - 1).5 = 4 + 17.5 = 89

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Carol's starting pay for her summer job is $10.25 per hour. Carol earns exactly 3 raises this summer.
zlopas [31]
We know that
1) <span>Carol's starting pay for her summer job is $10.25 per hour
</span><span>Carol earn per hour=$10.25 per hour
</span><span>
2) </span><span>For the first rise, she receives a 50 cent-per-hour raise
10.25+0.50=10.75
</span>Carol earn per hour=$10.75 per hour

3) <span>For the second rise, she receives a 10% raise per hour
10.75*1.10=11.825
</span>Carol earn per hour=$11.825 per hour

4) <span>For the third rise, she receives another 50 cent-per-hour raise
11.825+0.50=12.325
</span>Carol earn per hour=$12.325 per hour

5) At the start of next summer. She will be given a 5% raise per hour based on her pay at the end of this summer. <span>
12.325*1.05=12.94125
</span>Carol will earn per hour=$12.94 per hour

the answer is
$12.94 per hour
4 0
3 years ago
You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this?
puteri [66]

Answer:

15

Step-by-step explanation:

lets begin to set up this question. i personally find questions like these easiest when i begin to set up ideas to help my brain process it better, for example:

person a

person b

person c

person d

we know that each (person) must receive at least 1 candy. we also know that we have 7 candies. therefore if we want do draw this out :

person a- 1

person b- 1

person c- 1

person d -1

notice that we now have given away 4 of the 7 candies. now we have 3 candies left. we can simply:

person a- 2

person b-2

person c-2

person d- 1

but, keep in mind that there are still many more ways that we can distribute the candies to other kids. the question we are asked is how may ways can we do this. since i have already illustrated the question, you can either learn how to put this into an equation, or experiment how many variations there are. the answer, either way is 15.

4 0
3 years ago
What is the quotient of 3227/555? What is the repetend?
slega [8]

Answer:

A repeating or recurring decimal is decimal representation of a number whose digits are periodic (repeating its values at regular intervals) and the infinitely repeated portion is not zero. It can be shown that a number is rational if and only if its decimal representation is repeating or terminating (i.e. all except finitely many digits are zero). For example, the decimal representation of

1

/

3

becomes periodic just after the decimal point, repeating the single digit "3" forever, i.e. 0.333.... A more complicated example is

3227

/

555

, whose decimal becomes periodic at the second digit following the decimal point and then repeats the sequence "144" forever, i.e. 5.8144144144.... At present, there is no single universally accepted notation or phrasing for repeating decimals.

The infinitely repeated digit sequence is called the repetend or reptend. If the repetend is a zero, this decimal representation is called a terminating decimal rather than a repeating decimal, since the zeros can be omitted and the decimal terminates before these zeros.[1] Every terminating decimal representation can be written as a decimal fraction, a fraction whose divisor is a power of 10 (e.g. 1.585 =

1585

/

1000

); it may also be written as a ratio of the form

k

/

2n5m

(e.g. 1.585 =

317

/

2352

). However, every number with a terminating decimal representation also trivially has a second, alternative representation as a repeating decimal whose repetend is the digit 9. This is obtained by decreasing the final (rightmost) non-zero digit by one and appending a repetend of 9. 1.000... = 0.999... and 1.585000... = 1.584999... are two examples of this. (This type of repeating decimal can be obtained by long division if one uses a modified form of the usual division algorithm.[2])

Step-by-step explanation:

4 0
3 years ago
What is the probability of flipping a coin 12 times and getting heads 3 times? Round your answer to the nearest tenth of a perce
attashe74 [19]
<h3>Answer: A) 5.4%</h3>

==================================

Explanation:

We use the binomial probability formula here

P(k) = (n C k)*(p)^k*(1-p)^(n-k)

In this case, there are n = 12 trials and p = 0.5 is the probability of getting heads. The value of k = 3 means we want 3 heads.

So,

P(k) = (n C k)*(p)^k*(1-p)^(n-k)

P(3) = (12 C 3)*(0.5)^3*(1-0.5)^(12-3)

P(3) = 220*(0.5)^3*(1-0.5)^(12-3)

P(3) = 0.0537109375

P(3) = 0.054

P(3) = 5.4%

-----------------

Side note: the n C k refers to the nCr combination formula

_n C _r = \frac{n!}{r!*(n-r)!}

where the exclamation marks mean factorials. You could also use Pascal's Triangle as an alternative for this portion.

6 0
3 years ago
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