QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles


X axis is the ones that goes left and right
(x,y)
symetric about the x axis means that the vertical distance from the x axis is the same for 2 points that are symetric about the x axis
y is height
(x,y)
(5,2)
2 is height
distance from x axis
therefor the other point is -2
(5,-2)
the other vertex is at (5,-2)
All you have to do is do the distributive property. So, for the first one you would do 5 times x which equals 5x and then you would do 5 times 4 which equals twenty. All you are left with is the addition sign. Your full equation now would be 5x+20
Answer:
the second graph (c)
Step-by-step explanation: