Answer:
ok so its the first one
Step-by-step explanation:
it shows th same kind of aleration
Answer: 
Step-by-step explanation:
Given : Sample size : n= 33
Critical value for significance level of
: 
Sample mean : 
Standard deviation : 
We assume that this is a normal distribution.
Margin of error : 
i.e. 
Hence, the margin of error is 
Answer:
x = 21/8
Step-by-step explanation:
Step 1: Write equation
x - 11 = 3 - 7(x - 1)
Step 2: Solve for <em>x</em>
<u>Distribute -7:</u> x - 11 = 3 - 7x + 7
<u>Combine like terms:</u> x - 11 = 10 - 7x
<u>Add 7x on both sides:</u> 8x - 11 = 10
<u>Add 11 on both sides:</u> 8x = 21
<u>Divide both sides by 8:</u> x = 21/8
D=y2-y1
D+y1= y2-y1+y1 add y1 to both sides to cancel it out.
D+y1=y2 that drops -y1 for the right side but the left remains.
And that's your answer.
Answer:
x = -1 and y = 1
Step-by-step explanation:
5x + 2y = -3 . . . . . . . (i)
x + 5y = 4 . . . . . . . (ii)
- Finding x in terms of y from eq. (ii) :-
x + 5y = 4
x = 4 - 5y
- Placing this value of x in eq. (i) :-
5(4 - 5y) + 2y = -3
20 - 25y + 2y = -3
-23y = - 23
<u>y = 1</u>
- Placing the value of y in eq. (i)
5x + 2(1) = -3
5x + 2 = -3
5x = - 5
<u>x = -1</u>