Question

Lynn is trying to determine how far away Student B is from the balloon. He decides to use the

Answer 1

Answer:

Did you get the answer If so please give it to me.

Step-by-step explanation:

Answer 2

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the image that illustrates the scenario is not given.

However, I can deduce that the question is about a right-angled triangle.

So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.

For triangle A (solve for b)

Using cosine formula.

$\cos \theta = \frac{Adjacent}{Hypotenuse}$

$\cos 60= \frac{5}{b}$

Make b the subject

$b= \frac{5}{\cos 60}$

For triangle B (solve for b)

Using cosine formula.

$\sin \theta = \frac{Opposite}{Hypotenuse}$

$\sin 60= \frac{b}{5}$

Make b the subject

$b = 5\sin 60$

For triangle C (solve for b)

Using cosine formula.

$\tan \theta = \frac{Opposite}{Adjacent}$

$\tan 60= \frac{b}{5}$

Make b the subject

$b = 5\tan 60$