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3 years ago

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of .

Mathematics

2 answers:

Oliga [24]3 years ago

5 0

Answer:

Answer is III line

$x - 3y - 7 = 0$

Step-by-step explanation:

Given that the line passes through (1,-2)

Hence when we substitute x=1 and y =-2 the equation should be satisfied

I equation

$3x - y - 7 = 0\\3(1)-(-2) \neq 7\\x - 3y + 7 = 0\\1-3(-2)+7 = 14 \neq 0x - 3y - 7 = 0\\1-3(-2)-7 =0\\$

Hence third equation is the correct answer.

hjlf3 years ago

4 0

The correct question is
What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3

we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0

the answer is
x - 3y - 7 = 0

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4 years ago

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Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are . If point D

polet [3.4K]

Given:
A has coordinates (-6,5)
C has coordinates (3.6,-0.4).
C divides AB in the ratio 3:2.

Refer to the diagram shown below.
The coordinates of B are determined by
$\frac{3.6-(-6)}{x-(-6)} = \frac{3}{3+2} \\ \frac{9.6}{x+6} = \frac{3}{5} \\ 3(x+6) = 48 \\ 3x +18=48 \\ x=30/3=10$
Also,
$\frac{5-(-0.4)}{5-y} = \frac{3}{5} \\ 3(5-y) = 27 \\ 15-3y=27 \\ y= \frac{12}{-3} =-4$

Answer:
The coordinates of B are (10,-4).

Now, we know the coordinates of line segment AB as A (-6, 5) and B (10,-4).
D (x,y) divides AB in the ratio 4:5.
Therefore
$\frac{x-(-6)}{10-(-6)} = \frac{4}{4+5} \\ \frac{x+6}{16} = \frac{4}{9} \\ 9(x+6)=64 \\ 9x+54=64 \\ x=1.11$
Also,
$\frac{5-y}{5-(-4)} = \frac{4}{9} \\ 5-y = 4 \\ y = 1$

Answer:
The coordinates of D are (1.11, 1)

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3 years ago

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HELP

damaskus [11]

Answer:

I think it is 12 and 1/3 and 121 over 3

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3 years ago