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suter [353]
3 years ago
12

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of .

Mathematics
2 answers:
Oliga [24]3 years ago
5 0

Answer:

Answer is III line

x - 3y - 7 = 0

Step-by-step explanation:

Given that the line passes through (1,-2)

Hence when we substitute x=1 and y =-2 the equation should be satisfied

I equation

3x - y - 7 = 0\\3(1)-(-2) \neq 7\\x - 3y + 7 = 0\\1-3(-2)+7 = 14 \neq 0x - 3y - 7 = 0\\1-3(-2)-7 =0\\

Hence third equation is the correct answer.

hjlf3 years ago
4 0
The correct question is
<span>What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3
</span>
we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0

the answer is
<span>x - 3y - 7 = 0</span>
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