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aev [14]
3 years ago
7

Please help i will mark brainliest

Mathematics
1 answer:
Evgen [1.6K]3 years ago
4 0

Answer:

2. \left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]

3. \left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]

4. \left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]

Step-by-step explanation:

2. This matrix is easy, as it just requires addition.

\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]    +     \left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]   =  \left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]

3. This matrix requires for the matrices to be multiplied first, then added.

\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]    +     \left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]     =   \left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]

4.  Here we can add the last 2 matrices to find x.

\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]   +   \left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]  = \left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]

Hope this helps! (Please consider giving brainliest)

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