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liq [111]
3 years ago
15

Someone answer this plz, ill be ur frend

Mathematics
1 answer:
Lorico [155]3 years ago
4 0

Answer:


Step-by-step explanation:


The first thing you need to do is classify all the men into 4 groups which are:

1) 30 and younger with facial hair: 4

2) older than 3 with facial hair: 5

3) 30 and younger with facial hair: 3

4) older than 30 without facial hair: 4



Question (a): Make a two-way table of the data. Of the men surveyed, how many were 30 and younger? How many did not have facial hair.


                                  with facial hair          without facial hair          total

30 & younger                         4                                     3                          7

older than 30                         5                                     3                          8

total                                        9                                    6                          15

From the data you can see that:

7 men were 30 and younger and 6 men did not have facial hair.



Question (b): Create a two-way relative frequency table that displays the relative frequency of the men 30 and younger and of the men older than 30 who had or did not have facial hair. Express your answer as decimals written to three decimal places.


                              with facial hair          without facial hair          total

30 and younger             .267                           .200                       0.467

older than 30                  .333                           .200                      0.533

total                                0.600                        0.400                        1.000



Question c: What percent of men older than 30 had facial hair?

The percent is equal to the relative frequency times 100% so in this case it is equal to (1/3) * 100% = 33.33%

I hope this helps

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