now, let's notice the larger "yellow" semicircle, it has a gap, the gap on the right is of a semicircle with a diameter of 10, BUT it also has a descender on the left, a part that's hanging out, that part is also a semicircle.

so if we use the descending semicircle to fill up the gap on the right, we'll end up with a filled up larger semicircle, whose diameter is 20, and whose radius is 10 cm.

$\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=10 \end{cases}\implies A=\pi 10^2\implies A=100\pi \\\\\\ \stackrel{\textit{half of that for a semicircle}}{A=\cfrac{100\pi }{2}}\implies A=50\pi \implies \stackrel{\pi =3.142}{A=157.1}$

8 0

3 years ago

Please help, i do not get this.

Artyom0805 [142]

Answer:

k(x) = |x - 4| - 2

Step-by-step explanation:

So we know that k(x) is shifted 4 untis to the right and 2 units down. In an absolute value function, the value you move to the left will be positive and the value you move to the right will be negative. Since we are moving to the right, our value will be negative.

When you shift the function up or down, you will either subtract or add that value out side the absolute value. Since we are shifting down 2 units, that means we will be subtracting by 2.

Best of Luck!

3 0

3 years ago

What is the image of (-3,-7)(−3,−7) after a reflection over the x-axis?

kodGreya [7K]

Answer is ( -3, 7)
Rule for reflection over x axis is
x , y to x, -y
Since the y value is already negative it will change to positive

See attachment

5 0

2 years ago

Rick wants to use multiplication to solve k=7÷1/3​

Rick wants to use multiplication to solve k=7÷1/3