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4 years ago

I will mark brainliest!

Mathematics

1 answer:

stira [4]4 years ago

3 0

Answer:-5

Step-by-step explanation:

the cirrrect answer is negative 5

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How do I work this math problem? (9 x 10 to the sixth power) (8 x 10 negative 4 power?

Kamila [148]

90^6=531441000000

80^-4= 1/80^4= 1/4960000
For this, use negative power rule x^-a= 1/x^a

7 0

3 years ago

A music player was marked down by 1/4 of the original price.

shepuryov [24]

Answer:

Step-by-step explanation:

marked down by 1/4 of the original price.

let x represent original price

original price - 1/4 of original price = sales price

x - 1/4x = 128

4/4x - 1/4x = 128

3/4x = 128

x = 128/(3/4)

x = 128 * 4/3

x = 512/3

x = 170.666 rounds to 170.67 <== original price

==============================

I hope I am understanding this one correctly...

let x = price the store paid

x + 1/2x = 170.67

2/2x + 1/2x = 170.67

3/2x = 170.67

x = 170.67 / (3/2)

x = 170.67 * 2/3

x = 341.34/3

x = 113.78 <=== what the store paid

===========================

the difference between the discount price..I am assuming this is the $ 128 from part A.....and what the store paid....113.78...from part B..

128 - 113.78 = $ 14.22 <==

I am not completely sure about B and C......B confused me.....and if B is wrong, so is C.

6 0

3 years ago

Read 2 more answers

The slope of line is -1/3. what is an equation of a line that is perpendicular to line of t

-BARSIC- [3]

Answer:

well you have to use y=mx and plugg your numbers in

Step-by-step explanation:

sorry its not much help

6 0

3 years ago

For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4

Elina [12.6K]

Answer:

C. $(5-\frac{1}{2})^6$

Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

$Sum = 2 + 4$

$Sum = 6$

Each term of a binomial expansion are always of the form:

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

Where n = the sum above

$n = 6$

Compare $15(5)^2(-\frac{1}{2})^4$ to the above general form of binomial expansion

$(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......$

Substitute 6 for n

$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

$a^{n-r} =(5)^{6-4}$

$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

$b = \frac{-1}{2}$

Substitute values for a, b, n and r in

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

$(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

Check the list of options for the expression on the left hand side

The correct answer is $(5-\frac{1}{2})^6$

3 0

3 years ago

Will works 7 hours a day, 6 days a week. He is paid £9.20 an hour. He shares his wages with his Mum in the ratio Will : Mum = 5

frez [133]

It will take him 6 weeks to buy the car

4 0

4 years ago