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Anettt [7]
4 years ago
15

I will mark brainliest!

Mathematics
1 answer:
stira [4]4 years ago
3 0

Answer:-5

Step-by-step explanation:

the cirrrect answer is negative 5

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How do I work this math problem?<br> (9 x 10 to the sixth power) (8 x 10 negative 4 power?
Kamila [148]
90^6=531441000000

80^-4= 1/80^4= 1/4960000
For this, use negative power rule x^-a= 1/x^a
7 0
3 years ago
A music player was marked down by 1/4 of the original price.
shepuryov [24]

Answer:

Step-by-step explanation:

marked down by 1/4 of the original price.

let x represent original price

original price - 1/4 of original price = sales price

x - 1/4x = 128

4/4x - 1/4x = 128

3/4x = 128

x = 128/(3/4)

x = 128 * 4/3

x = 512/3

x = 170.666 rounds to 170.67 <== original price

==============================

I hope I am understanding this one correctly...

let x = price the store paid

x + 1/2x = 170.67

2/2x + 1/2x = 170.67

3/2x = 170.67

x = 170.67 / (3/2)

x = 170.67 * 2/3

x = 341.34/3

x = 113.78 <=== what the store paid

===========================

the difference between the discount price..I am assuming this is the $ 128 from part A.....and what the store paid....113.78...from part B..

128 - 113.78 = $ 14.22 <==

I am not completely sure about B and C......B confused me.....and if B is wrong, so is C.

6 0
3 years ago
Read 2 more answers
The slope of line is -1/3. what is an equation of a line that is perpendicular to line of t
-BARSIC- [3]

Answer:

well you have to use y=mx and plugg your numbers in

Step-by-step explanation:

sorry its not much help

6 0
3 years ago
For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4
Elina [12.6K]

Answer:

<em>C.</em> (5-\frac{1}{2})^6

Step-by-step explanation:

Given

15(5)^2(-\frac{1}{2})^4

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

Sum = 2 + 4

Sum = 6

Each term of a binomial expansion are always of the form:

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

Where n = the sum above

n = 6

Compare 15(5)^2(-\frac{1}{2})^4 to the above general form of binomial expansion

(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......

Substitute 6 for n

(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

By direct comparison of

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

and

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

We have;

^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4

Further comparison gives

^nC_r = 15

a^{n-r} =(5)^{6-4}

b^r= (-\frac{1}{2})^4

[Solving for a]

By direct comparison of a^{n-r} =(5)^{6-4}

a = 5

n = 6

r = 4

[Solving for b]

By direct comparison of b^r= (-\frac{1}{2})^4

r = 4

b = \frac{-1}{2}

Substitute values for a, b, n and r in

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

Solve for ^6C_4

(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em>(5-\frac{1}{2})^6<em />

3 0
3 years ago
Will works 7 hours a day, 6 days a week. He is paid £9.20 an hour. He shares his wages with his Mum in the ratio Will : Mum = 5
frez [133]
It will take him 6 weeks to buy the car
4 0
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