To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)
We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
Student's error is –5 < x.
Solution:
Step 1: Given inequality
31 < –5x + 6
Step 2: Subtract 6 from both sides of the inequality.
31 – 6 < –5x + 6 – 6
25 < –5x
Step 3: Multiply both sides by –1 to reverse the inequality.
25 × (–1) > –5x × (–1)
–25 > 5x
Step 4: Divide by 5 on both sides.
–5 > x
The correct answer is –5 > x.
Student's error is –5 < x.
Answer:
The method is to multiply the numbers by there varible
Step-by-step explanation:
Answer:
im in a challenge
Step-by-step explanation:
Answer:
Patrick from spongebob? He dosent do work
Step-by-step explanation:
