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matrenka [14]
4 years ago
6

Paul can type 60 words per minute and Jennifer can type 80 words per minute. How does Paul's typing speed compare to Jennifer's?

Mathematics
2 answers:
MA_775_DIABLO [31]4 years ago
6 0
- - You have: 60:80

Solve:

Divide each of these bight the HCD (20)


After that you get: 3:4

Now because you get the ratio of 3:4 it means than 
1 second=3 words -Paul
1 second=4 words -Jennifer's





kap26 [50]4 years ago
5 0
Paul does not compare to Jennifer. Jennifer is supreme. 

nah but seriously a 60:80 when divided by 10 is 6:8. Divide that by 2 and its 3:4. Therefore Jennifer is 1/4 times faster or 20 words/per minute faster that Paul.<u>
</u>
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Round to the nearest given place.<br> 1.80431<br><br> thousandths
rodikova [14]
In order to round a number to the nearest thousandths, we have to check the number in the ten thousandths place:
1- If the number in the ten thousandths is less than 5, then the thousandths number will remain the same and all numbers after it will be converted to zeroes.
2- If the number in the ten thousandths is equal to or greater than 5, then the thousandths number will be incremented by 1 and all numbers after it will be converted to zeroes.

Applying this to the given number: 
<span>1.80431
</span>The number in the ten thousandths position is 3 which is less than 5.
Therefore, rounding <span>1.80431 to the nearest thousandths will be:
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3 years ago
Help! f(x)=x^2 what is g(x)
Ede4ka [16]

Answer:

C.) g(x) = 3x^2

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3 years ago
Please answer! Thanks!
Karo-lina-s [1.5K]

Answer:

26.4 m

Step-by-step explanation:

The sine of an angle is the ratio between the opposite side of the angle and the hypotenuse. Hence,

sin 40° = \frac{opposite}{hypotenuse}

            = \frac{17}{c}

         c = \frac{17}{sin40}

       <u>  c = 26.4 m (3 sf)</u>

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Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.
Salsk061 [2.6K]

Given that the two functions are f(x)=9x+2 and g(x)=-9x^2-2x+1

We need to determine the value of (f \circ g)(-6)

<u>The value of </u>(f \circ g)(x)<u>:</u>

The value of (f \circ g)(x) can be determined using the formula,

(f \circ g)(x)=f[g(x)]

Substituting g(x)=-9x^2-2x+1 in the above formula, we get;

(f \circ g)(x)=f[-9x^2-2x+1]

Now, substituting x=-9 x^{2}-2 x+1 in the function f(x)=9x+2, we get;

(f \circ g)(x)=9(-9x^2-2x+1)+2

(f \circ g)(x)=-81x^2-18x+9+2

(f \circ g)(x)=-81x^2-18x+11

Thus, the value of (f \circ g)(x) is (f \circ g)(x)=-81x^2-18x+11

<u>The value of </u>(f \circ g)(-6)<u>:</u>

The value of  (f \circ g)(-6) can be determined by substituting x = -6 in the function (f \circ g)(x)=-81x^2-18x+11

Thus, we have;

(f \circ g)(-6)=-81(-6)^2-18(-6)+11

(f \circ g)(-6)=-81(36)-18(-6)+11

(f \circ g)(-6)=-2916+108+11

(f \circ g)(-6)=-2797

Thus, the value of  (f \circ g)(-6) is -2797

Hence, Option B is the correct answer.

8 0
4 years ago
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