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Phantasy [73]
3 years ago
7

If,(2√3)p=78,then find p?​

Mathematics
1 answer:
Simora [160]3 years ago
3 0
P = 13 √3 hope this helped please mark me brainliest!
You might be interested in
Thank you if you can help
finlep [7]
It answer is perfect
7 0
3 years ago
Find volume and where to draw a line to separate a and b<br>​
Travka [436]

26 x 21 x 15

= 8,190 ft^3

Volume is 8,190 ft^3

4 0
4 years ago
Your cellular phone contract calls for a flat monthly service charge of $10.95 plus $0.12 per minute for calls within a certain
wariber [46]

Answer:

For 100 calls the monthly cost = 10.95 + 0.95(100) = $ 22.95

120 calls = 10.95 + 0.95(120) = $ 25.35

140 calls = 10.95 + 0.95(140) = $ 27.75

160 calls = 10.95 + 0.95(160) = $ 30.15

Therefore it is constant

The answer is B. Yes, the average rate of change is constant

Hope this helps!

4 0
3 years ago
Read 2 more answers
A motion picture camera at normal speed takes 24 pictures per second. How many pictures are in a movie that is 90 minutes long?
ad-work [718]
24 × 60 = 1,440
1,440 × 90 = 129,600

There are 129,600 pictures in a movie that is 90 minutes long.
4 0
3 years ago
Read 2 more answers
The diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 mi
Assoli18 [71]

Answer:

Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

Step-by-step explanation:

We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.

<em>Firstly, Let X = diameters of ball bearings</em>

The z score probability distribution for is given by;

          Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = mean diameter = 106 millimeters

            \sigma = standard deviation = 4 millimeter

Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)

    P(X > 111) = P( \frac{ X - \mu}{\sigma} > \frac{111-106}{4} ) = P(Z > 1.25) = 1 - P(Z \leq 1.25)

                                                  = 1 - 0.89435 = 0.1056

Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

4 0
3 years ago
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