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insens350 [35]
3 years ago
8

Write and solve an equation to answer the question, "39.2 is what percent p of 112?" An equation is __ =p⋅ __. The solution is p

= __, or __%.
Mathematics
2 answers:
Roman55 [17]3 years ago
6 0
It would be X=0.35=25%
andrey2020 [161]3 years ago
5 0
39.2 = 112x

x = 0.35 = 35%
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8.2 is 10% of what number
Tatiana [17]
8.2 is 10% of 82

As 8.2 * 10 is 82.
4 0
4 years ago
Read 2 more answers
the equation of a line is y=-1/2x+6. Write an equation in point-slope form for the same line. Explain the steps that you used.
Citrus2011 [14]
Y = -1/2x + 6.....the slope is -1/2 and the y int = 6 or (0,6)

y - y1 = m(x - x1)
slope(m) = -1/2
(0,6)....x1 = 0 and y1 = 6
now we sub
y - 6 = -1/2(x - 0) <==

** You basically just label ur variables and sub them into the point slope form


4 0
3 years ago
Does anyone need my help on anything that isnt math right now?​
dexar [7]

Answer: you can change the subject so that you can help people with other subjects

Step-by-step explanation:

8 0
3 years ago
Please help me i need to find the area of shaded region please help me​
Montano1993 [528]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=13\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)\\A=84-24\\A=60\ ft^2

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)\\A=96-16\\A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)\\A=80+16\\A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)\\A=225-81\\A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(4)(2)\\A=21-8\\A=13\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)\\A=(49\pi -33)\ in^2

6 0
3 years ago
A researcher randomly assigned N = 16 rodents to experience one of four levels of shock (n = 4 per group) following the illumina
Umnica [9.8K]

Answer:

The hypothesis should be retained

Step-by-step explanation:

We are given:

N= 16

n = 4

SS_B_G = 24

SS_E = 48

Level of significance, a = 0.05

From the given data, our ANOVA table will be:

----Source: Between---- Residual---

------DF:n-1=> 4-1=3------N-n=>16-4=12

------SS: SS_B_G = 24---- SS_E =48

----MS: MS_B_G = 8----MS_E=48/12=4

Note: proper ANOVA table is attached

The statistic will be written as:

TS = \frac{MS_B_G}{MS_E} ~ F_n_-_1, _N_-_n

T = 8/4 = 2

Therefore

F_n_-_1, _N_-_n, _a

=> F_3,_1_2,_ 0_._0_0_5 = 3.490

The hypothesis should be retained, because we no know that the statistic is in the acceptance area.

7 0
3 years ago
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