(7)(-6)......simplify please

Mathematics

1 answer:

lapo4ka [179]2 years ago

5 0

It’s just 7 times negative 6 so the answer is negative 42

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the function p(t)=3(e^0.0866t describes how to find the pollution level p(t) in relation to any time t, where t is the number of

ddd [48]

The pollution level in 1980 was 7.13 to the nearest hundredth ⇒ answer c

Step-by-step explanation:

The function $p(t)=3(e^{0.0866t})$ , where

p(t) is the population level at any time t
t is the number of years after 1970

We need to find the pollution level in 1980

∵ $p(t)=3(e^{0.0866t})$

∵ t is the number of years after 1970

∴ t = 1980 - 1970 = 10 years

- Substitute the value of t in the equation above

∴ $p(t)=3(e^{0.0866*10})$

∴ $p(t)=3(e^{0.866})$

∴ p(t) = 7.13214 ≅ 7.13 to the nearest hundredth

The pollution level in 1980 was 7.13 to the nearest hundredth

Learn more:

You can learn more about the functions in brainly.com/question/8520610

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2 years ago

Cameron is a member of a national gardening club. she asked 200 of her fellow members whether they use compost to fertilize thei

krok68 [10]

Using the z-distribution, it is found that the 90% confidence interval for the true proportion of club members who use compost is (0.392, 0.508).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so the critical value is z = 1.645.